Consider the reaction: A + B → products From the following data obtained at a certain temperature, determine the order 2. of the reaction and calculate the rate constant. [A] 1.50 1.50 [B] 1.50 2.50 Rate (M/s) 3.20 x 101 3.20 x 101 6.40 x 101 3.00 1.50
Consider the reaction: A + B → products From the following data obtained at a certain temperature, determine the order 2. of the reaction and calculate the rate constant. [A] 1.50 1.50 [B] 1.50 2.50 Rate (M/s) 3.20 x 101 3.20 x 101 6.40 x 101 3.00 1.50
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter14: Chemical Kinetics: The Rates Of Chemical Reactions
Section14.4: Concentration-time Relationships: Integrated Rate Laws
Problem 14.5CYU: Sucrose, a sugar, decomposes in acid solution to give glucose and fructose. The reaction is...
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Where did n=0 and m=1 come from? Thank you so much got confused here
![The gaseous reaction, A2 → 2A, is first order in A2. After 751 seconds. 64.7%
1.
of Az remains undecomposed. Calculate
a) the half-life
b) the length of time required to decompose 90% of A2
Consider the reaction: A + B → products
From the following data obtained at a certain temperature, determine the order
2.
of the reaction and calculate the rate constant.
Rate (M/s)
3.20 x 101
3.20 x 101
6.40 x 101
[A]
1.50
[B]
1.50
1.50
2.50
3.00
1.50](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F93aad3a1-5559-4a87-8a46-568ba5611d2c%2F5a551ed7-32eb-49c3-a731-737a5f25cfa8%2F3mbhe9r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The gaseous reaction, A2 → 2A, is first order in A2. After 751 seconds. 64.7%
1.
of Az remains undecomposed. Calculate
a) the half-life
b) the length of time required to decompose 90% of A2
Consider the reaction: A + B → products
From the following data obtained at a certain temperature, determine the order
2.
of the reaction and calculate the rate constant.
Rate (M/s)
3.20 x 101
3.20 x 101
6.40 x 101
[A]
1.50
[B]
1.50
1.50
2.50
3.00
1.50
![11:15 PM O
0.0KB/s .l ll6 29
rate = K[A]m[B]"
Step2
b)
A + 6 >
Prodeucs
Yate = k TAT T67"
onder =
m+n
from te valuu givu
3-20 xlo = k l1:5]M [I-5]M
330 x lo =K TI-5]M r2-5]n 10
6.40 x lo = K [ 3JM [1:5]" →0
Equation O
équatiom O
3 10 xto
3- Ło x lo
. In =ol
Equaition O - equation O
26.40xto!
320xTo -
2 = 127m
a den
- M+n = I+0 = 1
Using equatiau
640 x lo = K 3]'- 1-5]"
6.40 xlo1 = 3K
k= 213 x lol s-1
Step3
c)
order = 1
Rate constant = 2.13 × 10-1 s1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F93aad3a1-5559-4a87-8a46-568ba5611d2c%2F5a551ed7-32eb-49c3-a731-737a5f25cfa8%2Fd180zt_processed.jpeg&w=3840&q=75)
Transcribed Image Text:11:15 PM O
0.0KB/s .l ll6 29
rate = K[A]m[B]"
Step2
b)
A + 6 >
Prodeucs
Yate = k TAT T67"
onder =
m+n
from te valuu givu
3-20 xlo = k l1:5]M [I-5]M
330 x lo =K TI-5]M r2-5]n 10
6.40 x lo = K [ 3JM [1:5]" →0
Equation O
équatiom O
3 10 xto
3- Ło x lo
. In =ol
Equaition O - equation O
26.40xto!
320xTo -
2 = 127m
a den
- M+n = I+0 = 1
Using equatiau
640 x lo = K 3]'- 1-5]"
6.40 xlo1 = 3K
k= 213 x lol s-1
Step3
c)
order = 1
Rate constant = 2.13 × 10-1 s1
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