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- For the following table of data. x 1 2 3 4 5 6 7 8 9 10 y 0 0.5 1 2 2.5 3 3 4 4.5 5 a. draw a scatterplot. b. calculate the correlation coefficient. c. calculate the least squares line and graph it on the scatterplot. d. predict the y value when x is 11.Find the equation of the regression line for the following data set. x 1 2 3 y 0 3 4The accompanying data resulted from an experiment in which weld diameter x and shear strength y (in pounds) were determined for five different spot welds on steel. A scatterplot shows a pronounced linear pattern. The least-squares line is = -964.98 + 8.60x. Because 1 lb = 0.4536 kg, strength observations can be re-expressed in kilograms through multiplication by this conversion factor: new y = 0.4536(old y). What is the equation of the least-squares line when y is expressed in kilograms? (Give the answer to two decimal places.) = x 202.9 212.9 222.9 232.9 242.8 y 814.5 786.1 961.2 1118.8 1077.0
- A world wide fast food chain decided to carry out an experiment to assess the influence of income on number of visits to their restaurants or vice versa. A sample of households was asked about the number of times they visit a fast food restaurant (X) during last month as well as their monthly income (Y). The data presented in the following table are the sums and sum of squares. (use 2 digits after decimal point) ∑ Y = 393 ∑ Y2 = 21027 ∑ ( Y-Ybar )2 = SSY = 1720.88 ∑ X = 324 ∑ X2 = 14272 ∑ ( X-Xbar )2 = SSX = 1150 nx=8 ny=11 ∑ [ ( X-Xbar )( Y-Ybar) ] =SSXY=1090.5 PART A Sample mean income is Answer Sample standard deviation of income is Answer 90% confidence interval for the population mean income (hint: assume that income distributed normally with mean μ and variance σ2) is [Answer±Answer*Answer] 90% confidence interval for the population variance of income (hint: assume that income distributed normally with mean μ and variance σ2) is…Each of the following pairs represents the number of licensed drivers (X) and the number of cars (Y) for seven houses in my neighborhood: Drivers X Cars Y 5 4 5 3 2 2 2 2 3 2 1 1 2 2 Construct a scatterplot to verify a lack of pronounced curvilinearity. Determine the least squares equation for these data. (Remember, you will first have to calculate r, SSy, and SSx) Determine the standard error of estimate, sy|x, given that n = 7. Predict the number of cars for each of two new families with two and five drivers.Suppose the manager of a gas station monitors how many bags of ice he sells daily along with recording the highest temperature each day during the summer. The data are plotted with temperature, in degrees Fahrenheit (°F), as the explanatory variable and the number of ice bags sold that day as the response variable. The least squares regression (LSR) line for the data is =-114.05+2.17X. On one of the observed days, the temperature was 85 °F and 66 bags of ice were sold. The number of bags of ice predicted to be sold by the LSR line, y, when the temperature is 85 °F is 70. Using the predicted value, compute the residual at this temperature. Answer:
- Suppose the manager of a gas station monitors how many bags of ice he sells daily along with recording the highest temperature each day during the summer. The data are plotted with temperature, in degrees Fahrenheit (F), as the explanatory variable and the number of ice bags sold that day as the response variable. The least squares regression (LSR) line for the data is Bags = -151.05 +2.65Temp. On one of the observed days, the temperature was 82 °F and 68 bags of ice were sold. Determine the number of bags of ice predicted to be sold by the LSR line, Bags, when the temperature is (82\ \text (°F. J\\) Enter your answer as a whole number, rounding if necessary. Bags = 1.11 residual Incorrect Using the predicted value you just found, compute the residual at this temperature. 1.11 Incorrect ice bags ice bagsThe proiessur of an introductory statistics course has found something interesting: there may be a relationship between scores on his first midterm and the number of years the test-takers have spent at the university. For the 64 students taking the course, the professor found that the least-squares regression Español equation relating the two variables number of years spent by the student at the university (denoted by x) and score on the first midterm (denoted by y) is y = 82.52- 2.53x. The standard error of the slope of the least-squares regression line is approximately 1.55. %3D Test for a significant linear relationship between the two variables by doing a hypothesis test regarding the population slope B,: (Assume that the variable y follows a normal distribution for each value of x and that the other regression assumptions are satisfied.) Use the 0.05 level of significance, and perform a two- tailed test. Then complete the parts below. (If necessary, consult a list of formulas.) Aa…Suppose the least squares regression line for predicting weight (in pounds) from height (in inches) is given by Weight= -110+3.5*(height) Which of the following statements is correct? l. A person who is 61 inches tall will weigh 103.5 pounds ll. For each additional inch of height, weight will decrease on average by 3.5 pounds. lll. There is a negative linear relationship between height and weight. a) l and lll only b) l and ll only c) ll only d) l only e) ll and lll only
- Find the equation of the least-squares line for the stride length and speed of camels given in the table below. Use the equation of the least-squares line from to predict the average speed (in meters per second) of a camel with a stride length of 3.7 meters. Round your results to the nearest tenth of a meter per second.The least squares regression line for the cost of a diamond necklace from a department store (y, in dollars) in the year xyears since 2000 is given by yˆ=1823+314x. Interpret the y-intercept of the least squares regression line. Select the correct answer below: The predicted cost of a diamond necklace from the department store is expected to increase $314 per year after the year 2000. The predicted cost of a diamond necklace from the department store in the year 2000 is $1823. The predicted cost of a diamond necklace from the department store in the year 2000 is $314. The y-intercept should not be interpreted.Use five decimal places Fit the following data by the equation y=(a*x)/(b+x) using the Least squares method x 2 4 10 13 y 15 32 40 24