Cost for two machines are given below: Machine A First cost Salvage value Annual operation Annual maintenance Taxes and insurance Life, years Money is worth at least 10 %. Determine: a) b) c) P20,000 2,000 3,000 1,200 3% 8 Machine B Rate of return on additional investment Uniform annual Cost of Machine A and Machine B Which is more economical P30,000 3,000 2,500 1,000 3% 12

Cost for two machines are given below: Machine A First cost Salvage value Annual operation Annual maintenance Taxes and insurance Life, years Money is worth at least 10 %. Determine: a) b) c) P20,000 2,000 3,000 1,200 3% 8 Machine B Rate of return on additional investment Uniform annual Cost of Machine A and Machine B Which is more economical P30,000 3,000 2,500 1,000 3% 12

Essentials Of Investments

11th Edition

ISBN:9781260013924

Author:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.

Publisher:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.

Chapter1: Investments: Background And Issues

Section: Chapter Questions

Problem 1PS

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Similar questions

Compare the machines below using present worth analysis at i10% per year and find which one should be selected Machine Y First Cost Operating Cost Savage Lfe cycle Machine X 20.000 3.000 3.000 3years Firat Cost 30.000 .000 Annuel Operating Cost Salvage Life cycle 3.000 6 yoars
Question 3. Choose the best piping systems as shown in the table below using Annual Worth method (MARR: 6%). Concrete piping UPVC piping Initial cost (OR) Ca Initial cost (OR) Annual 0&M (OR/y)" 10000 Annual O&M (OR/yr) 5000 Rehabilitation cost at the 120000 5th year Useful life (years)¤ 10 Useful life (years)= 20 Ca 1720102 1136000 1828000:
RLC Manufacturing is planning to purchase a cutting equipment. Information are as follows: Equipment 1 Equipment 2 First Cost P 12,000 P 18,000 Salvage Value P 600 P 2,000 Annual Operation P 3,200 P 2,500 Annual Maintenance P 1,200 P 1,000 Taxes & Insurance 3% 3% Life, years 10 15 Money is worth at least 16%. Which equipment should be selected? Use: a. Rate of Return Method Rate of Return Method Annual Cost Method NOTE: Show cashflow diagram.
Maintenance costs for a machine with an expected 10-year life are estimated to be $1,700 each year for the first 5 years Followed by a $2,000 expenditure in year 8 and a $2,500 expenditure in the year 10. What is the equivalent present worth cost? Assume i= 6% per year. Select one: O a.-10,233 O b.-11.497 Oc-9,812 O d.-8,127 O e.-6863
2. Choose from the two machines which is more economical? Machine A Machine B P 8,000 P 14,000 15 15 0 2,000 P 3,000 P 1,200 3% First Cost Life Salvage Value Annual Operation P 2,400 Annual Maintenance P 1,000 Taxes and Insurance 3% Which will you choose if minimum required profit is 16%. Use Rate of Return on Additional Investment, Annual Cost Method and Present Worth Method
6. Compare the following three alternatives by the IRR method, given MARR of 6%/year. First find if they are feasible and then compare them with the incremental rate of retum method (AROR). Construction cost S Benefits S/yr Salvage S Alt. Service Life (yrs) 510,000 145,000 -10,000 775.000 155,000 15,000 1,075,000 165,000 20,000 6.
a- At 10%, find PW for the following Table Warehouse cost equipment cost Installation cost Annual maintenance costs Annual Revenues Salvage Machine life 0 1 2 3 -90,000 b- A project with an IRR = 20%, it has the following NCF (S) X X 4000 (SUS) 50,000 46.000 Find X? 6,500 8,000 45,000 15,000 15 years
Its required to select one of the two machines, if you know that the firms MARR-12% and if the costs are shown below: Project A Project B Initial cost, $ 7650 12900 Maintenance cost, S/year 1200 900 Salvage value, $ 2000 Economic life, year 4 Compare the two-alternative using: 1-Equavlent Annual worth comparison. 2- Present worth comparison
Using the following two relationships: AW = CR + A of AOC CR = -P(A/P,i,n) + S(A/F,i,n) %3D Calculate the Annual Worth (AW) based on the data for the following project: Corporate MARR = 10% Initial Investment Cost $1,000,000 Anticipated Project Life = 10 years Salvage Value at the end of 10 years $100,000 Annual Cost of Operation %3D $50,000 10% Compound Interest Factors
2. It is rëquired to select one of the three machines. Which machine should be selected, based on the present worth comparison at an interest rate of 12% per year, if the costs are shown below? Туре X 7,650 1,200 Туре Y 12,900 900 2,000 Туре Z 17,000 750 First cost, $ Maintenance cost,.( $ lyear) Salvage value, ( $) Economic (years) 4,000 12 4
Consider the following projects. The incremental ROR of the difference is most nearly. Most nearly number for answer. First Cost Life Annual benefit Annual Maintenance cost 1,000 Salvage Value 0.9% O 13% O 12% O 11% O No correct answer A O 10% 10,000 4,000 1.000 10 years B 16,593.4 6,000 2,000 3,000 10 years 1hm
In an energy systems installation, following financial requirement was identified. Capital cost of equipment and installation - $ 150,000 Recurrent cost of maintenance Replacement of parts Life time of the system Income through energy generation i. iii. -$5,000 per year -$4,000 per year - 12 years - $ 22,000 per year Calculate the payback period of the system. If the scarp value of the equipment is $ 5,000, determine is the net profit expected to be collected for the investment? Explain how this profit is affected by "cost of money" or "interest". No calculations needed.

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