Plz solve this problem within 20 minutes I have to submit it within 25 minutes will definitely voteup thanks ? ? ? could u please explain how is the final equationgotten. What is Vex and how are the equationsfor Vout and Vex obtained. When are the signsnegative and positive. Hope u can do a step bystep explantion with illustrations. Thank you inadvance.VeRearrangeFigure 9.23 Dynamic unbalanced bridge circuit.Figure 9.23 Dynamic unbalanced bridge circuit.Vout= i₁R₁-1₂R₂ = -1₁R₁+1₂R₂Vex i₁(R₁ + R₂) = ₂(R₂ + R₂)R₁R₁ + R₁Vout= VThe differential bufferamplifier provideshighinput impedance (i.e.,-out it does not load thedifferentialbufferamplifierdifferentialbufierR₂R₂ + Rbridge) and high gainfor the small changein voltage due to thesmall change inresistance.

Answered: Image /qna-images/answer/8b656295-642b-4239-9da8-3bc8cae776bc.jpg

could u please explain how is the final equation gotten. What is Vex and how are the equations for Vout and Vex obtained. When are the signs negative and positive. Hope u can do a step by step explantion with illustrations. Thank you in advance. differential buffer amplifier Figure 9.23 Dynamic unbalanced bridge circuit. ■ Rearrange R₂ The differential buffer amplifier provides high input impedance (i.e., You it does not load the bridge) and high gain for the small change in voltage due to the small change in resistance. differential buffer amplifier Figure 9.23 Dynamic unbalanced bridge circuit. Vout= i₁R₁-i₂R₂ = -i₁R₁+1₂R₂ V = i,(R₁ + R₂) = i₂(R₂ + R₂) ex R₂ Vout = V₁R₁+R₂ R₂ + R

could u please explain how is the final equation gotten. What is Vex and how are the equations for Vout and Vex obtained. When are the signs negative and positive. Hope u can do a step by step explantion with illustrations. Thank you in advance. differential buffer amplifier Figure 9.23 Dynamic unbalanced bridge circuit. ■ Rearrange R₂ The differential buffer amplifier provides high input impedance (i.e., You it does not load the bridge) and high gain for the small change in voltage due to the small change in resistance. differential buffer amplifier Figure 9.23 Dynamic unbalanced bridge circuit. Vout= i₁R₁-i₂R₂ = -i₁R₁+1₂R₂ V = i,(R₁ + R₂) = i₂(R₂ + R₂) ex R₂ Vout = V₁R₁+R₂ R₂ + R

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter6: Power Flows

Section: Chapter Questions

Problem 6.61P

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