Create a non-abbreviated logic diagram for the following Boolean Expressions. You can use all gates. a’b + ab’ ((ab)’(b’c)’ + a’b’c’) (a +b)(a’ + c)(b’ + c’)
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Create a non-abbreviated logic diagram for the following Boolean Expressions. You can use all gates.
- a’b + ab’
- ((ab)’(b’c)’ + a’b’c’)
- (a +b)(a’ + c)(b’ + c’)
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- Simplify the following expressions by applying Boolean rules. ĀB + (A + B)4- [ From Boolean Algebra, x. (y+z) is equivalent to: a) none b) x. (y.z) c) x.y+x.z d) (x+y)+(x+z)Create a non-abbreviated logic diagram for the following Boolean Expressions. You can use all gates. • a'b+ ab' ((ab)'(b'c) + a'b'c') (a +b)(a' + c)(b' + c') (a e b+b e d)
- Q1: Let F1 = X., F2 = AB, F3 = F1+F2 Implement the above Boolean expression with logic circuit giving the truth table. ***Q1: Let F1 =X.V, F2 A OB, F3 F1+ F2 Implement the above Boolean expression with logic circuit . giving the truth table.Part 2: Simplify logic expression using Boolean rules F=(A B)(A B+C)C This function can be simpliled into Logic Expression: Logic Diagram
- Question 8: Draw the circuit that implements each of the following equations: B + AC' (W + Y)' + X' (B + A'D) + (BC)' (W' + XY)' + (VWX' + Z)'A bank burglar alarm (A) is to activate if it is after bank hours (H) and the front door is opened (F) orif it is after banking hours (H) and the vault door is opened (V).Construct the Truth Table for A(H, F, V), write the Boolean logic equation and draw the logiccircuit that represents the situation above.Evaluate the Boolean expression (A + 1) .(A + 0) =
- Q3: A majority circuit is a combinational circuit whose output is equal to 1 if the input variables have more 1's than 0's. The output is 0 otherwise. Answer 3 of the following questions: A- Design a 3-input majority circuit by finding the circuit's truth table, Boolean equation, and a logic diagram? B- Program and determine how many Configurable logic block (CLB) you wouid need for such circuit in Part A to be implemented in the FPGA then program this FPGA to emulate 3-input majority if you know that the CLB structure are: Look-Up Table (LUT) MUX A+B-t OLR C- Redesign the logic circuit of Part A using universal logic gate NOR?Simplify the given Boolean Expression: 2. A.(A + B') + A'B' + A' Simplify the above expression using basic properties only.6. For the following Verilog code, draw the corresponding circuit diagram for "bigMod". Your circuit should only involve standard gates (AND, OR, NAND, NOR, XOR, Inverter), and the variable names Val, X, Y, and Z. DO NOT SIMPLIFY THE CIRCUIT. Note: all of the code is legal Verilog, with no errors. module tstMod (F, A, B, C); output logic F; input logic A, B, C; assign F endmodule = (A & ~B & C) | (A & C) | ~B; module bigMod (Val, X, Y, output logic Val; input logic X, Y, Z; logic T; Z); .C (Y)); tstMod T1 (.F (T), .A (X), .B (1'bl), tstMod T2 (.F (Val), .A(Z), .B (T), .C (X)); endmodule