Current Attempt in Progress The following reaction is investigated to determine its rate law: 2NO(g) + 2H2(3) –→N2(3) + 2H2O(3) Experiments yielded the following results: Initial Concentrations (mol L-') Initial Rate of Formation of N, (mol L-s-) [NO] [H,1 0.40 x 10-4 0.30 x 10-4 1.0 x 10- 0.80 x 10-4 0.30 x 10-4 4.0 x 10- 0.80 x 10-4 0.60 x 10-4 8.0 x 10- What is the rate law for the reaction? O rate = k [NO][H2]? %3D O rate = k [NO]?[H2] %3! O rate = k [NO]?(H2]? O rate = k (NO][H2] %3D What is the value of the rate constant? k = i x 105 O Lmol 1s-1 O s1 O L'mol 3s1 O mol Ls-1 O L? mol-2s-1

Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter11: Chemical Kinetics
Section: Chapter Questions
Problem 11.35PAE: 11.35 For the reaction 2 NO(g) + 2 H?(g) — N,(g) + 2 H,O(g) at 1100°C, the following data have been...
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Current Attempt in Progress
The following reaction is investigated to determine its rate law:
2NO(g) + 2H2(g) → N2(g) + 2H2O(g)
Experiments yielded the following results:
Initial Concentrations (mol L-1)
Initial Rate of Formation of N,
(mol L-s-)
[NO)
[H,1
0.40 x 10-4
0.30 x 10-4
1.0 x 10-
0.80 x 10-4
0.30 x 10-4
4.0 x 10-
0,80 x 10-4
0.60 x 10-4
8.0 x 10-
What is the rate law for the reaction?
O rate = k [NO][H2]²
O rate = k [NO]?[H2]
O rate = k (NO]?[H2]?
O rate = k (NO][H2]
What is the value of the rate constant?
k= i
x 105
O L mol 1s1
O s-1
O L³mol 3s1
O mol L1s-1
O L² mol-2s 1
Transcribed Image Text:Current Attempt in Progress The following reaction is investigated to determine its rate law: 2NO(g) + 2H2(g) → N2(g) + 2H2O(g) Experiments yielded the following results: Initial Concentrations (mol L-1) Initial Rate of Formation of N, (mol L-s-) [NO) [H,1 0.40 x 10-4 0.30 x 10-4 1.0 x 10- 0.80 x 10-4 0.30 x 10-4 4.0 x 10- 0,80 x 10-4 0.60 x 10-4 8.0 x 10- What is the rate law for the reaction? O rate = k [NO][H2]² O rate = k [NO]?[H2] O rate = k (NO]?[H2]? O rate = k (NO][H2] What is the value of the rate constant? k= i x 105 O L mol 1s1 O s-1 O L³mol 3s1 O mol L1s-1 O L² mol-2s 1
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