Data Collection Generations Population Size 189 Population Size Proportion R allele 0.55 Proportion r allele 0.45 Prop. rr Genotype 0.17 110 Prop. Rr Genotype 0.56 Prop. RR Genotype 0.27 245 Generations Allele Proportion Genotype Proportions 245 Generations Rr RR IT Have either of the alleles become fixed? Why or why not? Did this population experience any bottlenecks? Briefly explain. Describe a plausible, ecological explanation for this selective pressure

Data Collection Generations Population Size 189 Population Size Proportion R allele 0.55 Proportion r allele 0.45 Prop. rr Genotype 0.17 110 Prop. Rr Genotype 0.56 Prop. RR Genotype 0.27 245 Generations Allele Proportion Genotype Proportions 245 Generations Rr RR IT Have either of the alleles become fixed? Why or why not? Did this population experience any bottlenecks? Briefly explain. Describe a plausible, ecological explanation for this selective pressure

Concepts of Biology

1st Edition

ISBN:9781938168116

Author:Samantha Fowler, Rebecca Roush, James Wise

Publisher:Samantha Fowler, Rebecca Roush, James Wise

Chapter19: Population And Community Ecology

Section: Chapter Questions

Problem 3ACQ: Figure 19.11 Age structure diagrams for rapidly growing, slow growing, and stable populations are...

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5 x P Parchment Exchange - Leader i earn.edgenuity.com/player/ nce - SC5181 A ņ X 1 2 3 4 5 Mark this and return G how would scientists describe th X How is point intercept used to determine the abundance of a population? OA sample of the population is counted by sight and then extrapolated into a value for the entire population. O A three-dimensional frame is placed next to the target species and is used to tally the number of individuals near it. OA predetermined scale is placed along a transect line and the percent cover of the desired species is measured. O A measured line is laid out in the study area and the number of target individuals underneath it are counted. O M Show is point intercept used to de x B + DELL Save and Exit Next Sign out English Submit Oct 27 K 2:2
QUESTION 7 You are working on an undergraduate project, studying an insect species. A recent study showed that the pigmentation pattern used for camouflage is made by an enzyme K. However, it has been shown that, when compared to the Kk individuals, the KK homozygotes would have a higher chance of dying from pigment overdose before growing up, while the kk individuals can easily fall to predation before becoming adults. In fact, when compared to the Kk individuals, the estimated selection coefficients for KK and kk are 0.25 and 0.5, respectively. You are interested in what would happen to these alleles. At present, you have conducted a population survey and have 1000 larvae in your collection. Among them, 360 are KK, 480 Kk and 160 kk. How many larvae would survive to adulthood? O 170 O 417 583 750 830 (Following up on Question 7.) What would be the KK genotype frequency at the adult stage? O 0.090 O 0.270 O 0.325 O 0.360 O 0.529 QUESTION 8
Figure 19.11 Age structure diagrams for rapidly growing, slow growing, and stable populations are shown in stages 1 through 3. What type of population change do you think stage 4 represents?
- SC5 X ET AET Login 9.core.learn.edgenuity.com/player/ cience - SC5181 A ent X + 1 2 3 4 5 v6.1.1-0050.20220124.mainline Ⓒ2022 Imagine Learning LLC Sudden change will affect the new population more severely due to the genetic bottleneck from a small population. The new population will be less genetically diverse than the original one since there are fewer alleles available. The populations would experience the same effects because all the bison that had been reproducing before the 12 bison left. Natural selection will affect the new population differently than it affects the original population. The new population will have less genetic drift than the original population because there are fewer genes. O O Question # 2 Multiple Select Suppose a population of 150 bison is wandering and grazing in an area where there is an old bridge across a river leading to a new field. After 12 bison make it across, the bridge collapses. Assuming equal numbers of males and females, what will most…
O Question 3. Is the population in H-W equilibrium? Observed genotype numbers A₁A1 =40 O Question 4: Is the population in H-W equilibrium? Observed number of each genotype ■ ● A1A2 =20 A2A2 = 40 ● A₁A1=36 A1A2=28 A₂A2=36 Note that raw numbers are given. The question is whether observed frequencies = expected frequencies. You must first compute the genotype frequencies.
Fiure es tional From: "Why our flu vaccines can't keep up" Which one of the graphs above shows the frequency of trait variation in the original sparrow population - the population before the storm hit? O Figure A • Figure B O Figure C
If these conditions held constant – what would the expected heterozygosity be in thepopulation today (2018 to deal with a clean integer value for generations)?1b. In 1884 the population had grown to 106 when disaster struck the island. Of the 19 adult menon the island, 15 were in the same fishing boat that capsized, leaving only 4 adult men alive onthe island. These desperate times may have changed the sex ratio of the breeding population onthe island. Let’s say that now, each man fathered children with an average of 1.5 differentwomen (male:female ratio of 1:1.5). If we start back with a heterozygosity of 0.5 from this point,given the effective population size on Tristan da Cunha, what is the expected heterozygosity inthe current population 7 generations later?1c. The scenarios described in 1a and 1b are examples of which two evolutionary phenomena,respectively?
udent Lab Riverwat x O Student Lab Riverwat x A Dashboard e' Theoretical Distributi X NUB- engagement as ure.com/courses/21405/quizzes/53484/take In a certain population (Niagara Gorge, Lewiston, NY) the allele for red striped (R) redback salamanders (Plethodon cinereus) is dominant to the unstriped grey (r) color allele. If this population of salamanders in Hardy-Weinberg equilibrium contains homozygous red salamanders (RR) at a frequency of 0.16, what is the frequency of the grey allele (r)? Edit View Insert Format Tools Table 12pt v Paragraph v BIU MacBook Pro I'm We &
3. To compare your observed results with those expected, you can use the statistical test, chi-square. Table 3 will assist in the calculation of the chi-square test. Note: To calculate chi-square you must use the actual num- ber of individuals for each genotype, not the frequencies. S d² d²le Observed value (0) Expected value (e) Deviation (o-e) = d Table 3 Chi-Square of Results from the Bead Model Chi-square (x²) = Edle 6 182 AA (1 18 -7 4.9 2.7 greater p=0.25 Aa 30 24 le зи 697 1.5 4.3 Degrees of freedom = 2 Level of significance, p < 0.05 estmanst 17 aa 4. Is your calculated x value greater or smaller than the given x² value for the degrees of freedom and p value for this problem? 6 /98.0 9 8 1 0,1
Amount of NH3 nces ne In a population of pansies, the red allele (CR) is incompletely dominant to the white allele (Cw). If the frequency of the red allele is 80%, what is the frequency of pink flowers in the population?* ds 1 and 2 20% Highschool MP3, 0.20 0.80 0.32 Fri O 0.16 When Charles Darwin visited the Galapagos Islands, he observed the marine OOO
A certain plant population has 289 individuals, some berry white flowers, other red flowers. The red allele is dominant over the white allele, of the 289 plants, 246 havve red flowers. Assuming the population is in equilibrium; i) What is the frequency of the white allele ii)How many of the red plants are expected to be heterozygous?
Lab Data Environment: Polluted Forest Typica Carbonaria Total Typica Carbonaria Moths Released q P Phenotype Frequency Allele Frequency 2pq p² 250 Moths 750 1000 Typica Carbonaria Carbonaria Allele Genotype Frequency d D dd Dd Color Genotype DD Light Dark G₁ 125 510 635 Color Light Dark Dark G₂ 88 735 823 Initial Frequency 0.50 Initial Allele Frequency 0.50 Moths Released 250 500 0.25 250 0.75 G3 83 885 968 Initial Frequency 0.25 0.50 0.25 G4 76 1042 1118 G5 29 1406 1435 Frequency G5 G5 Allele Frequency Frequency G5 Number of Moths G5