Design a PDA for the language L={w E {a, b, c}*|na(w)+ n(w) = nc()}.
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- L={a*b™a" | n,m=1,2,3....} is given. i) Write a CFG for the language L.Q3: Design machine M to recognize the language L= {w E (a, b)* every a in w is followed by at least two b'}Debug C language int func(int) main() { int num = 7, c; int f= func(num); printf("\n\n%d of %d\n\n", num, f); } int func(aj); { if(aj=1 aj=0) return 1; else return (aj*fun(aj-1); }
- debug c language main() { int m,n; for(i 0; i << 5; i++) { printf("\t\t\t\t"); for(j 0; j << 5; j+++) printf("*"); printf("/n"); }De 8ign a DFA for he folloaing language L={ w/we {r, B3* and # (w) iševen}#include <bits/stdc++.h>using namespace std;#define numVl 3 struct thNde { thNde* parent; int mat[numVl][numVl]; int x, y; int cost; int level;}; int thPrntMtrx(int mat[numVl][numVl]) { for (int q = 0; q < numVl; q++) { for (int j = 0; j < numVl; j++) printf("%d ", mat[q][j]); printf("\n"); }} thNde* newNode(int mat[numVl][numVl], int x, int y, int newX, int newY, int level, thNde* parent) { thNde* node = new thNde; node->parent = parent; memcpy(node->mat, mat, sizeof node->mat); swap(node->mat[x][y], node->mat[newX][newY]); node->cost = INT_MAX; node->level = level; node->x = newX; node->y = newY; return node;} int row[] = { 1, 0, -1, 0 };int col[] = { 0, -1, 0, 1 }; int calculateCost(int starting[numVl][numVl], int resltng[numVl][numVl]) { int count = 0; for (int q = 0; q < numVl; q++) for (int j = 0; j < numVl; j++) if (starting[q][j] && starting[q][j] != resltng[q][j]) count++; return count;} int isSafe(int x, int y) {…
- What language does the expression ((a * a) b) | b?This picture must demonstrate array and functions. Code this in C languageDesign Regular Expressions for the following languages. iii. Strings that contain ‘01’ as substrings at any place except at the beginning or at the end. It accepts 1010, 0101,110110, etc. but does not accept 01, 0110, 1101, 00, etc. Ʃ={0, 1}