Design a symmetrical CMOS reference inverter to provide a delay of 1.5 ns when driving a 12-pF load. Assume VDD= 3.3 V, VTN= -VTp= 0.45 V, and Kn= 100 µA/V2. (Round off the solution to two decimal places.) W 1/1 /1
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- A 10 mv, 2kHz sinussoidel signal is applied to the input of an op-Amp integrator having R = 50kQ and C=2µf. Find the output voltage.Question 2: a. Find DC resistance of a diode, if voltage applied across a Silicon diode at room temperature (300° K) is (7/100) V. Saturation current, at this temperature is (7×10-2)A. Consider n = 2 for Silicon diode and VT = 26 mV. b. Let an emf of (32) V is induced from a coil when the alternating current changes at the rate of (257) Ampere per second. Find the following: i. Inductance of the coil, and ii. Energy stored in the coil.a) The voltage across a 20µF capacitance is v. = 50 sin( at – 80°) volts and Frequency equal to 100 Hz. Determine the current through the capacitor iç and sketch its waveform. b) Define phasor
- The sample value of VOin is used for the PRESET for timer T2. T2 is used to sample a 4. When PB2 (NO) is activated momentarily, an analog input voltage, Voin (tag), is If Vlin > Vs , Vlin is applied to analog output OUTI, and timer Ti and T2 are reset. analog input voltage, Vlin (tag), Vsisa voltage stored in the PLC. sampled every 15 seconds by timer T1. VOin has a voltage range of (5.0 - 10.0 volts) and 26 a scale factor of 300.0 is reset. are Otherwise T1 and T2 continue to "run". PB2 can be used to restart TI if Vlin > Vs. Rehumberhuer the untet Develop a ladder logic program to solve this. RTO TI 15000 PB2 TI.DN AO TON TL HEN HON GRT TI.DNa) The voltage across a 10µF capacitance is ve = 150 sin( at – 509) volts and Frequency equal to 50 Hz. Determine the current through the capacitor iç and sketch its waveform. b) Define the term frequencyThe voltage across a parallel-plate capacitor with area A=800cm2 and separation d = 2 mm varies sinusoidally as V = (15 mV) cos (150t), where t is in seconds. Find the displacement current between the plates.
- A half wave rectifier is connected with a power supply of 50 Hz and provides a peak output voltage of 50V across a 500 ohm resistance. If it is required to design a capacitor filter which can limit peak to peak voltage across the load to 10 V , find capacitor value. With proper explanation and in 15 min.A certain type of capacitor is designed to filter low-frequency signals, impeding their transmission between circuits. a) What capacitance is needed to produce a 96 k2 reactance at a frequency of 122 Hz? nF b) What would its reactance be at 1.00 MHz?1. What is the RMS noise voltage associated with a 10 Q resistor at room temperature when the system has a bandwidth of 5 MHz?
- The pins 0, 1, 2 and 3 of part 4 of a microcontroller are connected with resistors to drive Vcco an LED at various intensities as shown in the figure. For Vcc=4.2 V and a voltage drop of 1.2 V across the LED, the range (maximum current) and resolution (step size) of the drive current are, respectively, (a) 4.0 mA and 1.0 mA (b) 15.0 mA and 1.0 mA (c) 7.5 mA and 0.5 mA (d) 4.0 mA and 0.5 mA μС A₂ A₁ A 0.75 k 1.5k 3k 6kReview I Constants A radio can be tuned into a particular station frequency by adjusting the capacitance in an L-C circuit. Suppose that the minimum capacitance of a variable capacitor in a radio is 4.14 pF . Part A What is the inductance L of a coil connected to this capacitor if the oscillation frequency of the L-C circuit is 1.70 MHz , corresponding to one end of the AM radio broadcast band, when the capacitor is set to its minimum capacitance? Express your answer in henrys to three significant figures.Activity 2: According to Ohm's low, the current (1) through an impedance (Z) is related to the voltage (V) across it as: V =1 ×Z. A voltage equal to 210e/0.2 Volts, is applied across a load of impedance (60 + jX) Ohms. The magnitude (i.e., modulus) of the current through it is measured as 3 Amperes. (2-a) Calculate all possible values of X. (2-b) Calculate the consumed reactive power (Q) using the formula: Q = Imag {V x I'}. Assume phase (i.e., argument) of the current equal to 67°.