Determine the pH of a solution of aspirin (acetylsalicylic acid, HC,H,O4) by constructing an ICE table, writing the equilibrium constant expression, and using this information to determine the pH. The Ka of aspirin is 3.3 × 10-4. Complete Parts 1-3 before submitting your answer. ( PREV NEXT > Based on your ICE table and the definition of Ka, set up the expression for Ka in order to determine the unknown. Each reaction participant must be represented by one tile. Do not combine terms. [0] [2.75 x 10-3+x] [0.0153 + x] [2.75 x 10-³] 1 [2.75 x 10-3-x] [0.0153 -x] 1 Ka [3.62 x 10-³] [1.53 x 10-5] 2 [15.3] 2 = 3.3 x 10-4 [0.0153] [3.62 x 10-3+x] [3.62 x 10-3-x] [1.53 x 10+x] [1.53 x 103 -x] 3 [x] [15.3 + x] RESET ermine the pH of a solution of aspirin (acetylsalicylic acid, HC,H,O4) by constructing am table, writing the equilibrium constant expression, and using this information to ermine the pH. The Ka of aspirin is 3.3 x 10-4. Complete Parts 1-3 before submitting r answer. 3 [2x] [15.3-x] ur ICE table and the equilibrium expression for Ka, determine the pH of the aspirin solu
Determine the pH of a solution of aspirin (acetylsalicylic acid, HC,H,O4) by constructing an ICE table, writing the equilibrium constant expression, and using this information to determine the pH. The Ka of aspirin is 3.3 × 10-4. Complete Parts 1-3 before submitting your answer. ( PREV NEXT > Based on your ICE table and the definition of Ka, set up the expression for Ka in order to determine the unknown. Each reaction participant must be represented by one tile. Do not combine terms. [0] [2.75 x 10-3+x] [0.0153 + x] [2.75 x 10-³] 1 [2.75 x 10-3-x] [0.0153 -x] 1 Ka [3.62 x 10-³] [1.53 x 10-5] 2 [15.3] 2 = 3.3 x 10-4 [0.0153] [3.62 x 10-3+x] [3.62 x 10-3-x] [1.53 x 10+x] [1.53 x 103 -x] 3 [x] [15.3 + x] RESET ermine the pH of a solution of aspirin (acetylsalicylic acid, HC,H,O4) by constructing am table, writing the equilibrium constant expression, and using this information to ermine the pH. The Ka of aspirin is 3.3 x 10-4. Complete Parts 1-3 before submitting r answer. 3 [2x] [15.3-x] ur ICE table and the equilibrium expression for Ka, determine the pH of the aspirin solu
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter16: Principles Of Chemical Reactivity: The Chemistry Of Acids And Bases
Section: Chapter Questions
Problem 127SCQ
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Question
![Determine the pH of a solution of aspirin (acetylsalicylic acid, HC,H,O4) by constructing an
ICE table, writing the equilibrium constant expression, and using this information to
determine the pH. The Ka of aspirin is 3.3 x 10-4. Complete Parts 1-3 before submitting
your answer.
PREV
NEXT
Based on your ICE table and the definition of Ka, set up the expression for Ka in order to determine the
unknown. Each reaction participant must be represented by one tile. Do not combine terms.
[0]
0
[2.75 x 10-3+x]
[0.0153 + x]
[2.75 x 10-³]
6.17
1
[2.75 x 10-3-x]
[0.0153 -x]
Ka =
1
[3.62 x 10-³]
[3.62 x 10-3+x]
[1.53 x 10-5]
---------
[3.62 x 10-a-x] [1.53 x 10-5+x] [1.53 x 10-5-x]
2.25 x 10-3
[15.3]
2.09 x 10-3
2
3
= 3.3 × 10-4
[0.0153]
Determine the pH of a solution of aspirin (acetylsalicylic acid, HC,H,O4) by constructing am
ICE table, writing the equilibrium constant expression, and using this information to
determine the pH. The Ka of aspirin is 3.3 x 10-4. Complete Parts 1-3 before submitting
your answer.
2.68
PREV
on your ICE table and the equilibrium expression for Ka, determine the pH of the aspirin solu
pH =
[x]
[15.3 + x]
5.05 x 10-5
3
RESET
[2x]
5.30
[15.3 -x]
RESET
12.2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb0140d99-b557-46d4-a2e7-675ca4b314d8%2F9cf68a4a-a369-47a4-9f63-fd24cb0a2717%2F8cje3do_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Determine the pH of a solution of aspirin (acetylsalicylic acid, HC,H,O4) by constructing an
ICE table, writing the equilibrium constant expression, and using this information to
determine the pH. The Ka of aspirin is 3.3 x 10-4. Complete Parts 1-3 before submitting
your answer.
PREV
NEXT
Based on your ICE table and the definition of Ka, set up the expression for Ka in order to determine the
unknown. Each reaction participant must be represented by one tile. Do not combine terms.
[0]
0
[2.75 x 10-3+x]
[0.0153 + x]
[2.75 x 10-³]
6.17
1
[2.75 x 10-3-x]
[0.0153 -x]
Ka =
1
[3.62 x 10-³]
[3.62 x 10-3+x]
[1.53 x 10-5]
---------
[3.62 x 10-a-x] [1.53 x 10-5+x] [1.53 x 10-5-x]
2.25 x 10-3
[15.3]
2.09 x 10-3
2
3
= 3.3 × 10-4
[0.0153]
Determine the pH of a solution of aspirin (acetylsalicylic acid, HC,H,O4) by constructing am
ICE table, writing the equilibrium constant expression, and using this information to
determine the pH. The Ka of aspirin is 3.3 x 10-4. Complete Parts 1-3 before submitting
your answer.
2.68
PREV
on your ICE table and the equilibrium expression for Ka, determine the pH of the aspirin solu
pH =
[x]
[15.3 + x]
5.05 x 10-5
3
RESET
[2x]
5.30
[15.3 -x]
RESET
12.2
Transcribed Image Text:Determine the pH of a solution of aspirin (acetylsalicylic acid, HC,H,O4) by constructing an
ICE table, writing the equilibrium constant expression, and using this information to
determine the pH. The Ka of aspirin is 3.3 x 10-4. Complete Parts 1-3 before submitting
your answer.
Initial (M)
Change (M)
Equilibrium (M)
-X
NEXT
>
652 mg of aspirin (HC9H₂O4) is dissolved in an aqueous solution of 237 mL aqueous solution. Fill in the ICE
table with the appropriate value for each involved species to determine concentrations of all reactants and
products.
15.3 - x
0
1
HCgH;O4(aq)
2.75 x 10-3+x
0.0153 + x
2.75 x 10-3
2.75 x 10-3-X
0.0153 - x
+
2
H₂O(1)
3.62 x 10-³
3.62 x 10-3+x
=
1.53 x 10-5
3.62 x 10-3-x
3
H3O+ (aq)
15.3
1.53 x 10-5 + x
0.0153
+
1.53 x 10-5-x
C9H₂O4 (aq)
RESET
+X
15.3 + x
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