Determine what type of filter the network shown below represents by determining the voltage transfer function. L vin O Band Pass Band Reject O High Pass O Low Pass R Vout
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- Given the complex numbers A1=630 and A2=4+j5, (a) convert A1 to rectangular form: (b) convert A2 to polar and exponential form: (c) calculate A3=(A1+A2), giving your answer in polar form: (d) calculate A4=A1A2, giving your answer in rectangular form: (e) calculate A5=A1/(A2*) giving your answer in exponential form.google.com/forms/d/e/1FAlpQLScF2Wzu92iVI-tEM2nxdhqXrGdR460G4QCTxaUZZeC678PqTg/formResponse مطلوب /06 *:The potential at point P due to Q1 and Q2 is Q, = 1x10-12C 0.5 m 0.5 m Qz = 1x10-12C %3D 50 cm 0.01797 V Ov O -0.01271 V O 0.01271 V O Insert PIC F10 F11 F12 F6 F7 FB Backspace 9 € P Enter H2_53528980697... -> For the circuit shown below, detemine the voltage of the -j10 2 capacitive reactance. -j5 0 ILOA(T) ==j102 jlon is Q 102 O 0.5L-90 52 A.
- Ro. 8. For unit- slep responses A,4 find the homafor the system. chowa ahe figure , 20 see tlJae) fimetion ofREC O x .002 w to Determine If 2 Events Are Independent: Substitute in what you know in to P(An B) = P(A) • P(B) and check to see if left side equals right side. o If it's equal, then it's independent. o If it's not equal, then it's not independent (or dependent). Let event M = taking a math class. Let event S = taking a science class. Then. M and S = taking a math class and a science class. Suppose P(M) = 0.6. P(S) = 0.5. and P(M and S) = 0.3. Are M and S independent? PCM)- P(S) = P(Mand5) .3 .3 indep endent .3 9. In a class, 60% of the students are female. 50% of all students in the class have long hair, 45% of the students are female and have long hair. Of the female students, 75% have long hair. Let F be the event that the student is female. Let L be the event that the student has long hair. One student is picked randomly. Are the events of being female and having long hair independent? ELMO1) The switch in the ciruit, shown in belou has been in Posikon "a" for a long hime. At t=0, the switch moves instantancously ho positron "b". Find volt) for t70 960n 1602 o.SmH 28V 12-5 nF 20v Volt)
- A Moving to another question will save this response. Quèstion 6 If we use phosphors(P15) for doping, then phosphors atoms are called donor atoms. True False A Moving to another question will save this response.Please, help with this problem. Do not give me an AI generated solution. I need an expert to help by explaining this problem step by step. The answers are provided: Yin1 = 20 + j15 mS Yin2 = -j10 mS Yin3 = 6.408 + j5.189 mS If the shorted section were open, Yin1 = 20 + j15 mS Yin2 = j10 mS Yin3 = 2.461 + j5.691 mSThe characteristic equation of sixth order system is as below find the stability of system. + 2s° + 8s4 + 12s + 20s? + 16s + 16 = 0
- The manimum value of the altenating wotaye and curent are 400 U and 20A respectvely s a cieritoanected to a svita supply . The ristantanerus values of the veltnge and current are 283V and 10 A respectvely of fime t=0, beth icreasing pesitively. 4) Write dan the gapressom for vwltaga and curend at pmet. b). Defermaned tha prver omsumed in the cranit. Take the velye and cunent to be ginusrida). fie P= VI end\ P = YI (PF)in V1 R2 100k SINE(0 10 100) R1 100k D1 D V2 0 out D D2 V3 0 DC offset[V]: 0 Amplitude[V]: 10 Freq[Hz]: 100 T delay[s]: Theta[1/s]: Phi[deg]: Ncycles: anter 2019-2220 Figure 3-5 Clipper Circuit for LTSPICE Simulation C4. To specify the type of simulation, select "Simulate>>Edit Simulation Cmd" from the menu. Choose "Transient" and enter 30m for Stop time, 0 for Time to start saving data, and 1m for Maximum Timestep. Click OK. C5. Click Run to start the analysis. C6. Place two voltage probes (voltage probes appear when placed on a wire during simulation), one at the input side (at the top of V1) and another at the output side (at the top of D2) of the circuit. What difference do you observe between the input and the output waveforms?D. Find h22. Express your answer in millisiemens to three significant figures. Enter your answer in rectangular form.