Dihybrid Basics TT or Tt = tall tt = short GG or Gg = green gg = white 1.) A tall green pea plant (TTGg) is crossed with a tall green pea plant (TtGg) FOIL each parent’s genotypes: tall green pea plant (TTGg) short white pea plant (TtGg) How many of the 16 offspring are: tall & green tall & white short & green short & white

Dihybrid Basics TT or Tt = tall tt = short GG or Gg = green gg = white 1.) A tall green pea plant (TTGg) is crossed with a tall green pea plant (TtGg) FOIL each parent’s genotypes: tall green pea plant (TTGg) short white pea plant (TtGg) How many of the 16 offspring are: tall & green tall & white short & green short & white

Name: Dihybrid BasicsTT or Tt = talltt = shortGG or Gg = greengg = white1.)
Uploaded: 2024-03-20T06:43:04.000Z
Channel: Bartleby
Description: Dihybrid BasicsTT or Tt = talltt = shortGG or Gg = greengg = white1.) A tall green pea plant (TTG9) is crossed with a tall green pea plant (TtGg)FOIL each parent’s genotypes:tall green pea plant (TTGg)short white pea plant (TtGg)How many of the 16 o

Biology 2e

2nd Edition

ISBN:9781947172517

Author:Matthew Douglas, Jung Choi, Mary Ann Clark

Publisher:Matthew Douglas, Jung Choi, Mary Ann Clark

Chapter12: Mendel's Experiments And Heredity

Section: Chapter Questions

Problem 24CTQ: Mendel performs a cross using a true-breeding pea plant with round, yellow seeds and a true-...

See similar textbooks

Similar questions

Mendel performs a cross using a true-breeding pea plant with round, yellow seeds and a true- breeding pea plant with green, wrinkled seeds. What is the probability that offspring will have green, round seeds? Calculate the probability for the F1 and F2 generations.
A pedigree analysis was performed on the family of a man with schizophrenia. Based on the known concordance statistics, would his MZ twin be at high risk for the disease? Would the twins risk decrease if he were raised in an environment different from that of his schizophrenic brother?
As it turned out, one of the tallest Potsdam Guards had an unquenchable attraction to short women. During his tenure as guard, he had numerous clandestine affairs. In each case, children resulted. Subsequently, some of the childrenwho had no way of knowing that they were relatedmarried and had children of their own. Assume that two pairs of genes determine height. The genotype of the 7-foot-tall Potsdam Guard was A9A9B9B9, and the genotype of all of his 5-foot clandestine lovers was AABB. An A9 or B9 allele in the offspring each adds 6 inches to the base height of 5 feet conferred by the AABB genotype. a. What were the genotypes and phenotypes of all the F1 children? b. Diagram the cross between the F1 offspring, and give all possible genotypes and phenotypes of the F2 progeny
type P = n! (p)* (q)"* х! (n - х)! Practice Problem: You cross a true-breeding pea plant with red flowers to a true-breeding pea plant with white flowers. All of your offspring have red flowers. Which gene is dominant? Why? What is the genotype of your offspring? You then cross the offspring to each other. What ratio do you expect? Why? You count 1000 plants and look at their flowers. Your results are as follows: 740 red 260 white Does this follow a simple Mendelian inheritance pattern? Why or why not? DADT 2 MEA SUDI ND D LUT IONS
Pea PlantsIn pea plants, a round-seed shape (R) is dominant over a wrinkled-seed shape (r). A round-seeded pea plant was crossed with another round-seeded pea plant. What are the genotype(s) and phenotype(s) ratios of the F1 generation? Show all possibilities using Punnett squares. State the F1 generation genotypes and phenotypes.
Purple flowers are dominant to white flowers. Identify the phenotypefor the following genotype Ff, FF, ff and determine if the genotype is heterozygous or homozygous. * For each row, you should select two columns. Purple flowers White flowers Heterozygous Homozygous Ff FF ff Brown eyes are dominant to blue eyes. Identify the phenotype for the following genotype BB, Bb, bb and determine if the genotype is heterozygous or homozygous. * 口ロ口
The trihybrid e+f+g+/efg is test crossed to the triple recessive efg/efg and the following genotypes were obtained in the progeny: efg = 2; efg = 28; e'fg* = 9; e*rg 32; efg 73; e*fg* = 10; ef g* =10; e'fg 2; %3D "The odd gene is The gene order is The gene distance between e-f is The gene distance between f-g is The gene distance between e-g is
If a homozygous tall pea plant is crossed with a homozygous shortpea plant, what are the possible genotype and phenotype of theoffspring? Legend: T- tall pea plant t- short pea plant Genotypes of the parents: TT x tt Question to answer ff: 1. What is the genotypic ratio? 2. What are the possible phenotypes of the offspring? 3. What is the phenotypic ratio?
A is dominant over a and B is dominant over b. Genes A/a and B/b assort independently. The parental cross (P) is between true- breeding (homozygous) strains (AA bb x aa BB). The resulting F1 offspring would be [Select ] A F1 x F1 cross gives the F2 generation. The ratio of phenotypes in the F2 generation can be described as [ Select ] In the phenotypic ratio, what number refers to individuals that are: dominant for both traits? [ Select ] recessive for both traits? [Select ] To what phenotypes do the "3"s in the ratio refer? [ Select ] > >
к, х Ааv AdBbCc AaBbCc No Spacing AaBbCc 三、相、 1 Normal Heading 1 Font Paragraph 6. Let's assume that the non-taster, daughter in question 5 is a carrier of the albino trait. She marries a Styles taster man, normally pigmented, whose mother was a non-taster albino. Show the cross between these parents. Genotype of the woman Genotype of the man Genotypes Phenotypes What is the chance that their child will be a taster? Footer What is the chance that their child will be albino? What is the chance that their child will be a taster albino? J.S.)
The genes responsible for albinism (A or a) and pink eyes (P or p) in mice are linked and wild-type pigmentation is dominant in both traits. A homozygous wild-type mouse is mated with an albino, pink-eyed mouse. The resulting F1 mice are crossed with albino, pink-eyed mice. The F2 progeny of this testcross are: 22 7 wild-type body color, wild-type eyes albino body color, wild-type eyes wild-type body color, pink eyes albino body color, pink eyes 10.000 3 18 How many cM apart are the albinism and pink-eye genes? O 50 O 40 O 30 O 20 O 10
Two pure-breeding lines of petunia plants are crossed. Line 1 plants grow to a height of 54 cm, and Line 2 plants grow to a height of 18 cm. Petunia plant height is controlled by three genes, A, B and C. Line 1 has the genotype A₁A₁B₁B₁C₁C₁, and line 2 has the genotype A2A2B₂B₂C₂C₂. Assume that genotype alone determines plant height under ideal growth conditions and that the alleles of the three genes are additive. If the F1 plants are self crossed, what is the expected proportion of F2 plants with the genotype A₁A₁B₁B₁C₁C₁ 1/8 1/32 1/16 1/4 1/64