Draw the amplitude bode plot of G(jω)=(10(1+0.1jω))/(2jω(1+0.5jω))
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Draw the amplitude bode plot of G(jω)=(10(1+0.1jω))/(2jω(1+0.5jω))
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- Find the Q of a circuit when the resonant frequency is 4.468 MHz, the inductance is 47 micro henrys and the resistance is 180 ohms in parallelIN A SERIES RLC CIRCUIT DRIVEN BY SINUSOIDAL INPUT SIGNAL, THE PHASE BETWEEN THE CURRENT AND THE INPUT VOLTAGE IS PLOTTED IN THE NEXT GRAPHAT FREQUENCY OF THE DRIVING (INPUT) VOLTAGE F= 1OKHZ THE PHASE BETWEEN THE CURRENT AND THE INPUT VOLTAGE IN RADIANS IS ABOUT: 1.6 1.2 0.8 0.4 -0.4 -0.8 -1.2 -1.6 1 10 100 1000 Frequency (f), kHz O g. 0.8 O b. 0.4 O c. 1.57 O d. 3.2 O e. zero pe. (0) aseydA resistor of resistance R=1000 2 is maintained at 17 °C and it shunted by 100 µH inductor. Determine the rms noise voltage across the inductor over a frequency bandwidth of: i) 15.9 kHz Ans: 182 x10-⁹ volt Ans: 9.22 x10-8 volt 11) 159 kHz iii) 1590 kHz Ans: 2.34 x10-6 volt
- 9. For each of the cascaded configurations shown below, determine the overall modulus and the output frequency. 1 kHz Overall Modulus = Frequency at point 3 = 100 kHz DIV 4 DIV 10 Overall Modulus = Frequency at point 4 = O DIV 8 DIV 10 DIV 2 DIV 10 3 DIV 2 421) Looking at the following circuit, select the correct Transfer fucntion. Please recognize that the answers are expressed in rectangular coordinates and not in magnitude, making this an easy problem. 21). ww w For the circuit in the given figure, assume L = 0.5 H and R= 200 kohm. ele O Vout (jw) Vin (jw) 200 k Vin R Vout –200 k+jw0.5 Vout (jw) ju0.5 200 k- jw0.5 Vin (jw) O Vout (ju) Vin (jw) - jw0.5 200 k– jw0.5 Vout (jw) 200 k Vin (jw) 200 k+jw0.55. For a 1Vpp sinusoidal input, at a frequency of 1KHz, draw the output for each circuit.
- In a series RLC circuit, the applied voltage is 108V. At resonance, the frequency is 200rad/sec, and the circuit current is 8.38 A. What is the resistance of the circuit (in Ohms)?Q1/ For the signal below, draw frequency and phase spectrum. w[t] = 10 – 20 cos(10nt – 30) +5 sin(70nt + 60)0.1 For the circuit shown, calculate CMi and C3 that required to obtain 177Hz lower critical frequency. Vee +9 V Poc = Bae = 125 Che= 25 pF C = 10 pF Re 220 1 Cs V 12 k RL 680 0 R. 50 Via RE 100 4.7 kf 10 uF
- 1-Find the center frequency and the two cutoff frequencies by changing the frequency until Vo becomes 0 and 0.707Vi respectively. 2- graph vo/vi and Theta against frequencyRepresent (-99)10 in a) Sign Magnitude form and b) Sign 1’s Complement form. c) Sign 2’s Complement form.Assuming that a vi sine signal of variable frequency is applied to the image circuit, it is necessary to calculate its gain as a function of w. What will be the gain in decibels when R1 = R2 = 1MQ, C1 = C2 = 1μF and w = 10rad³/ s 103 rad / s? answers: Avf = -120dB