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Draw the resonance of the folowing and explain the isomeres aroomaticity.
1. 1H-1,2,3-triazone
2. 3H-1,2,3-triazone
3. 4H-1,2,3-triazone
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- What is the appropriate systematic name for the compound below? HO., SH ) (15,45)-4-hydroxycyclohex-2-enethiol O (35,65)-6-mercaptocyclohexen-3-ol )(1S,4S)-4-mercaptocyclohex-2-enol (3S,65)-6-hydroxycyclohexene-3-thiolGive the reagents Br NO₂ 1) HNO3, H2S04 A) 2) Brz, Fe 3) Alcz 3) Br₂, Fe B) 1) HNO3, H₂504 2) といっ AlCl3 2) Biz,fe AlCl3 Ald 1) D)₂ 2) AND, H₂Sy 3) HND H₂SO 3) Biz, FeElectron-Poor Compounds: Hint ABCD Divide the compounds below into electron-poor and electron-rich groups. F H3C H3C A C ONa N=C-H E H₂C B D F LL CH3 H-Br MgBr Electron-Rich Compounds: F Check Answer View Solution
- Why should the 1,4-addition product be more stable than the 1,2-addition product? O O Br H IL H₂C=CH-CH-CH₂ 1,2-addition product Br H H₂C-CH:CH-CH₂ 1,4-addition product Because the two tetracoordinate sp³-hybridized carbons are farther apart in the 1,4 isomer reducting steric crowding. Because it is a disubstituted alkene and the 1,2 isomer is a monosubstituted alkene. O It shouldn't be more stable because it is a primary alkyl bromide and the 1,4 isomer is a secondary alkyl bromide.Click the "draw structure" button to launch the drawing utility. Under certain reaction conditions, 2,3-dibromobutane reacts with two equivalents of base to give three products, each of which contains two new 7 bonds. Product A has two sp hybridized carbon atoms, product B has one sp hybridized carbon atom, and product C has none. What is the structure of C? H 3HC C C=CH₂ edit structure ...H₂N. H3C. CH3 NH₂ H- CO₂H -CH3 NH₂ OH bime H₂N. OH CH3 Which of the following wedge-and-dash structures represents the Fischer projection shown below? IV H₂N. OH A) I B) II C) III D) IV
- Electrostatic potential maps of anisole and thioanisole are shown. Which do you think is the stronger acid, p-methoxybenzoic acid or p-(methylthio)benzoic acid? Explain.The double bond of an enamine (alkene + amine) is much more nucleophilic than a typical alkene double bond. Assuming that the nitrogen atom in an enamine is sp2hybridized, draw an orbital picture of an enamine, and explain why the double bond is electron-rich.What is the correct chiral designation for the following compound? axu a. (4R, 6R) b. (4S, 6S) c. (4R, 6S) d. (4S,6R)