E (eV) 0.00 -0.544 2 -0.850 4 4 3 -1.512 2- -3.401 Balmer series ENERGY

University Physics Volume 3
17th Edition
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:William Moebs, Jeff Sanny
Chapter9: Condensed Matter Physics
Section: Chapter Questions
Problem 80P: What is the critical magnetic field for lead at T = 2.8 K?
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The Balmer series for the hydrogen atom corresponds to electronic transitions that terminate in the state with quantum number n = 2 as shown in the figure below. Consider the photon of longest wavelength corresponding to a transition shown in the figure. (a) Determine its energy. eV (b) Determine its wavelength. nm Consider the spectral line of shortest wavelength corresponding to a transition shown in the figure. (c) Find its photon energy. eV (d) Find its wavelength. nm (e) What is the shortest possible wavelength in the Balmer series? (Be sure to consider all values of n, not just those indicated by the arrows in the figure.) nm 

E (eV)
0.00
-0.544 2
-0.850 4
4
3
-1.512
2-
-3.401
Balmer
series
ENERGY
Transcribed Image Text:E (eV) 0.00 -0.544 2 -0.850 4 4 3 -1.512 2- -3.401 Balmer series ENERGY
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