Electric Machine-check image, all question there. Consider the above equivalent circuit of IM. A three phase, Y connected , 215 V (line to line), 7.5Kw , 60Hz , three pole IM has the following parameter values in Ω/phase referred to the stator R1=0.294Ω , R2=0.144 Ω, X1=0.203 Ω, X2=0.409 Ω, Xm=10.25 Ω The total friction , windage and core losses may be assumed to be constant at 350W independent of load, For a slip s=0.02, compute the followings a)Stator current b)Power factor(pf) c)Rotor speed d)Power Output(shaft) e)Output(shaft) torque f)Efficiency

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
icon
Related questions
Question
100%

Electric Machine-check image, all question there.

Consider the above equivalent circuit of IM.

A three phase, Y connected , 215 V (line to line), 7.5Kw , 60Hz , three pole IM has the following parameter values in Ω/phase referred to the stator

R1=0.294Ω , R2=0.144 Ω, X1=0.203 Ω, X2=0.409 Ω, Xm=10.25 Ω

The total friction , windage and core losses may be assumed to be constant at 350W independent of load, For a slip s=0.02, compute the followings

a)Stator current

b)Power factor(pf)

c)Rotor speed

d)Power Output(shaft)

e)Output(shaft) torque

f)Efficiency

x,
X,
R,
i,(1)
R,
Fig. Equivalent Circuit of IM
Consider the above equivalent circuit of IM.
A three phase,Y connected, 215 V (line to line), 7.5 kW, 60 Hz, three pole IM has the following parameter values in 2/phase referred to the stator
R = 0.294 N, R = 0.144 N, X1 = 0.203 N, X, = 0.409 N, Xm = 10.25 2.
The total friction,windage and core losses may be assumed to be constant at 350 W independent of load. For a slip s = 0.02, compute the
followings
a) Stator Current
b) Power Factor(pf)
c) Rotor Speed
d) Power Output(Shaft)
e) Output(Shaft) Torque
f) Efficiency(n)
O a. I = 12.2135 – 12.2771i A, pf = 0.744373 , n, = 2312 rpm, Pahaft = 5209.49 w, T,haft = 21.1509 N. m, 7=0.86282
O b. I = 11.2135 – 12.2771i A, pf = 0.844373 , n, =
2352 rpm, Pahaft = 5209.49 W, T,haft = 21.1509 N. m, 7=0.79382
%3D
О с. — 11.152 — 12.5986i А, pf —D 0.4828 , п, —
1046 rpm, Pahaft = 3040.68 W, T,haft = 21.0056 N. m, 7=0.793137
O d. I = 16.2135 – 12.2771i A, pf = 0.844373 , n, =
2352 rpm, Pshaft = 5209.49 W, Tshaft = 21.1509 N.m, 7=0.86282
O e. I1 = 16.2135 – 12.2771i A, pf = 0.844373 , ng = 2250 rpm, Pahaft = 5009.79 W,
Tahaft
22.1509 N. m, 7=0.86282
%3D
Transcribed Image Text:x, X, R, i,(1) R, Fig. Equivalent Circuit of IM Consider the above equivalent circuit of IM. A three phase,Y connected, 215 V (line to line), 7.5 kW, 60 Hz, three pole IM has the following parameter values in 2/phase referred to the stator R = 0.294 N, R = 0.144 N, X1 = 0.203 N, X, = 0.409 N, Xm = 10.25 2. The total friction,windage and core losses may be assumed to be constant at 350 W independent of load. For a slip s = 0.02, compute the followings a) Stator Current b) Power Factor(pf) c) Rotor Speed d) Power Output(Shaft) e) Output(Shaft) Torque f) Efficiency(n) O a. I = 12.2135 – 12.2771i A, pf = 0.744373 , n, = 2312 rpm, Pahaft = 5209.49 w, T,haft = 21.1509 N. m, 7=0.86282 O b. I = 11.2135 – 12.2771i A, pf = 0.844373 , n, = 2352 rpm, Pahaft = 5209.49 W, T,haft = 21.1509 N. m, 7=0.79382 %3D О с. — 11.152 — 12.5986i А, pf —D 0.4828 , п, — 1046 rpm, Pahaft = 3040.68 W, T,haft = 21.0056 N. m, 7=0.793137 O d. I = 16.2135 – 12.2771i A, pf = 0.844373 , n, = 2352 rpm, Pshaft = 5209.49 W, Tshaft = 21.1509 N.m, 7=0.86282 O e. I1 = 16.2135 – 12.2771i A, pf = 0.844373 , ng = 2250 rpm, Pahaft = 5009.79 W, Tahaft 22.1509 N. m, 7=0.86282 %3D
Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Knowledge Booster
Electromagnetics Torque and Power
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Fundamentals of Electric Circuits
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:
9780078028229
Author:
Charles K Alexander, Matthew Sadiku
Publisher:
McGraw-Hill Education
Electric Circuits. (11th Edition)
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:
9780134746968
Author:
James W. Nilsson, Susan Riedel
Publisher:
PEARSON
Engineering Electromagnetics
Engineering Electromagnetics
Electrical Engineering
ISBN:
9780078028151
Author:
Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:
Mcgraw-hill Education,