mponent of nódalch element. There is no way of knowing the current throughwever, KCL must be satisfied at a sunernode like any other node. Hence a tdespernode in Fig. 3.5,i + i4 = i2 + i3(3.11a)v1 - v2v1 - v3v2 – 0v3 - 0(3.11b)6.To apply Kirchhoff's voltage law to the supernode in Fig. 3.4 we redraw the circuit asshown in Fig. 3.5. Going around the loop in the clockwise»direction gives-V2 + 5 + v3 = 0=v2 – V3 = 5(3.12)From Eqs. (3.10), (3.11b), and (3.12), we obtain the node volltages.5Vد مُسق ک من ؤFigure 3.5 Applying KVL to a supernode.Example 3.2: For the circuit shown in Fig. 3.6, find the node voltages.Solution:The supernode contains the 2-V source, nodes 1 and10 2www2, and the 10-2 resistor. Applying KCL to the2 Vsupernode as shown in Fig. 3.7(a) gives2.122 = i + iz +77 AExpressing in and iz in terms of the node voltages2 A22v1 - 0v2 - 02 =74or(3.2.1)V2 =-20 - 2vVIFigure 3.6 For Example 3.2.ESTHRER: ALI SHARAANMETHORS OF ANALYSISCHAPTER 3Kelemedgincerin

Find the unknown node voltage anc current. Here this problem is solving using node analysis.

Example 3.2: For the circuit shown in Fig. 3.6, find the node voltages. Solution: The supernode contains the 2-V source 10 2 ww 2, and the 10-2 resistor. Applying 2V supernode as shown in Fig. 3.7(a) gives 2 = i + iz + 7 Expressing i and iz in terms of the nod 7A 2A v2 – 0 v1 -0 2 + 7 %3D or --20 - 2v1

Example 3.2: For the circuit shown in Fig. 3.6, find the node voltages. Solution: The supernode contains the 2-V source 10 2 ww 2, and the 10-2 resistor. Applying 2V supernode as shown in Fig. 3.7(a) gives 2 = i + iz + 7 Expressing i and iz in terms of the nod 7A 2A v2 – 0 v1 -0 2 + 7 %3D or --20 - 2v1

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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