Answered: Example 9.3: Figure 9.30 represents the…

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter12: Subsurface Exploration

Section: Chapter Questions

Problem 12.13P

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Soil mechanics solution please

Transcribed Image Text:= 0.136 m S can also be calculated from the equation Boldos S=m, AH, = 0.81 x 0.25 x 3.0 = 0.135 m Example 9.3: Figure 9.30 represents the average soil profile obtained from boreholes, at the site of a proposed building whose foundation is to be placed at a depth of 2.5 m. The ground water table is at a depth of 3.5 m. It is estimated that the additional stress on the clay layer due to the weight of the building will be 150 kN/m² at the top of the clay and 70 kN/m² at the bottom of the clay. Following results were obtained from consolidation tests: 1+ eo 3.0x0.10 1+1.20 Applied stress (kN/m²) 25 Void ratio 0.890 0.882 0.865 0.830 0.798 Unit weights: sand above water table - 19.0 kN/m³; saturated sand - 21.0 kN/m³; clay- 19.5 kN/m³. Determine the settlement of the clay layer. El.0 mA IIN -2.5 m -3.5 m -5.5 m -11.5 m W.T.V 50 Building 100 Sand TIK TIK Clay TIK TIK Rock stratum Soil profile Fig. 9.30 Example 9.3 200 400 Y₁ = 19.0 kN/m³ Ysat = 21.0 kN/m³ 08:0 Ysat = 19.5 kN/m³ TIK TIK 800 0.765

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