i just need number 3 Exemple in 2D motion- MX Bike/Sand DuneV₁ = 60 mi/h = ? = " ? =seeh₂ = 10 m10mProblem Setup: MX-Bike is initiallymoving in horizontal direction.y (m)0V₂ = Vox10mkax.60 mi IhrVyhr 3600sectā=à = −(9.8 M/³² ) ĝX(m)X₁ = range.1610m = 27 m/s ~25 m/sImiSolution Break the motion down into the components inthe X-, ydirectionsVox= constat of the motion!Hmwk #1Voy = 0 leaving the dune.la1 = ay = 9.8 m/s²|y₁|=h₂ = 10m2)2 hoауVox3) Vy1) y(t) = y₂ + y₂ + + £ a₂t² → sy=h₂ = 1/2a₂+²;ay tayt^)t=2(10m)√√2¹ sec=1.414 secsolve fort!1x~ √x st = (27/1) (√²1 sec ) = ?√2(27) mAXst=?=? V² = V₂² + 2a(Y-Y₂)10m/5227 m/s=Q's time in air ? (1)what is the range?.time in the air? (2)Vy(fins 1)? (3)What is V.Lo Hmwk #1

Answered: Image /qna-images/answer/07e04cce-feed-41ce-9683-e85ec6d46284.jpg

Exemple in 2D motion MX Bike Sand Dune V₁ = 60 mi/h = ? = h₂ = 10 m 10m 0 Problem Setup: MX-Bike is initially moving in horizontal direction. ay (m) → V₂ = Vox 10m ках- m see Vy ? = 60 m Ihr hr 3600 sec ↓= -(9.8 M/²) ĝ ¥> X(m) Хf=range 1610m Imi = 27 m/s Solution Break the motion down into the components in the x-y- directions Hmwk #1 Vox= constant of the motion! Voy= = 0 leaving the dune. 2) ~25m/5 Vox ? v² = √² + 2a(y-Y.) la 1 = ay = 9.8 m/ 5² |y₁|=h₂ = 10m 1) y(t) = y₂ + ₁² + + £a₂t² → sy=h₂ = 1/2a₂t²") t= AX st fy=? ку Q's time in air ? (1) H What is the range? (2) • What is Vy (final) ? (3) Lo Hmuk #1 2h. ~ 2(10m) √2 sec=1.414 sec ay 10 m/s2 27 m/s X~ √x st = (27)(√²1 sα) = ? √2 (27) time in the air . solve fort! m

Exemple in 2D motion MX Bike Sand Dune V₁ = 60 mi/h = ? = h₂ = 10 m 10m 0 Problem Setup: MX-Bike is initially moving in horizontal direction. ay (m) → V₂ = Vox 10m ках- m see Vy ? = 60 m Ihr hr 3600 sec ↓= -(9.8 M/²) ĝ ¥> X(m) Хf=range 1610m Imi = 27 m/s Solution Break the motion down into the components in the x-y- directions Hmwk #1 Vox= constant of the motion! Voy= = 0 leaving the dune. 2) ~25m/5 Vox ? v² = √² + 2a(y-Y.) la 1 = ay = 9.8 m/ 5² |y₁|=h₂ = 10m 1) y(t) = y₂ + ₁² + + £a₂t² → sy=h₂ = 1/2a₂t²") t= AX st fy=? ку Q's time in air ? (1) H What is the range? (2) • What is Vy (final) ? (3) Lo Hmuk #1 2h. ~ 2(10m) √2 sec=1.414 sec ay 10 m/s2 27 m/s X~ √x st = (27)(√²1 sα) = ? √2 (27) time in the air . solve fort! m

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 53P: A surveyor measures the distance across a straight river by the following method: starting directly...

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