F1-100 2m F2=250 A 4m F3-200 F4=150 2,5m Find the forces acting on supports A and B in the figure. 3m B
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- PS2-5 Three forces are acting on the problem. List all of the simplifications that can be used in the problem. What is the simplest problem? F₂ 45° Rperpendicular to the page through the point o. (Let counterclockwise torque be positive and let forces to the right and up be positive. Use the following as necessary: the forces R, Write the necessary equations of equilibrium of the object shown in the figure below. Take the origin of the torque equation about an axis RFF, and F the length l of the object; and the angle e that the object makes with the horizontal.) EF, = = 0 Fy =0 Στ. =0 Need Help? Read ItQ5/A) From the figure below, determine the reaction force at pin C. A 000 0.6 m 10 kN 0.6 m 0.8 m 60° 0.4 m 6 kN OB
- 4. Forces F =F-20N and the third force F3 25N act on a cube with the side of a=2m. a. Find the screw driver (wrench) that is created by these forces i.e pitch, Mparallel, Mpapendicular b. Find the point of intersection of the axis of the wrench with the x-y plane. How do you check your answer is correct? G F D A B.A cargo ship is tied down to marine boll arts at a number of points along its length while its cargo is unloaded by a container handling crane. Each bollard is fastened to the wharf using anchor bolts. Three cables having known tension force magnitudes F, = ll0 kN.F, = 85kN.and F, 9OkNare secured to one bollard at a point A with coordinates (0.0.45 m. 0) in the x-r-: coordinate system shown in the figure part b. Each cable force is directed at an attachment point on the ship. Force F, is directed from point A to a point on the ship having coordinates (3 m, 9 m. 0) force F, is directed at a point with coordinates (6.5 m. 8.5 m. 2 m) and force F, is directed at a point with coordinates (8 m. 9 m. S m). The diameter of each anchor bolts is 4 24 mm. (a) Find the reaction forces and reaction moments at the base of the bollard. (b) Calculate the average shear stress in the anchor bolts (in the x-: plane). Assume each bolt cart ics an equal share of the total force.Determine completely the resultant of the forces acting on the step pulley in Figure 1-36. 750 lb 2 = 1- 60 - 250 lb 1250 lb Figure 1-36
- 4-61 Change the force F to {200i + 400j -700k}НОМE WORK 3 Determine the resultant force at A. for the figure below Hint : 1- Find the position of all points A,B.C (x, y., z) 2. Find Fas und FAC 3. Find Tanl and Iracl 4. Find FAg = F UA and Fac = F UAC 5- Finally find R and a, B.y 3m Fc= 500N FB= 500N 3m 5m 3m B 2m 4m 5mProblem 2-16 Resolve the force Fzinto components acting along the u and v axes and detemine the magnitudes of the components. Given: F1 = 250 N F2 = 150 N e1 = 30 deg 82 = 30 deg 8z = 105 deg
- The forces acting on the arm of an athlete doing shoulder exercises are shown in the figure. The athlete holds his arm at an angle of β=15° with the horizontal axis. Point O represents the axis of rotation in the shoulder joint, point A represents the connection point of the deltoid muscle to the humerus, point B represents the center of gravity of the arm, and point C represents the application point of the force acting on the hand. The distances between the rotation axis (O point) of the shoulder joint and the points A, B and C are a=20 cm, b =33 cm and c= 65 cm, respectively. The athlete's hand is exerted by a force of F= 150 N, which makes an angle of γ=30° with the vertical from the point C. The weight of the athlete's arm is W= 100 N. The direction of application of the Fm muscle force makes an angle of α=25° with the longitudinal axis of the arm. According to this; a) Calculate the FM muscle strength. b) Calculate the angle θ of the FJ joint reaction force with the horizontal.…The forces acting on the arm of an athlete doing shoulder exercises are shown in the figure. The athlete holds his arm at an angle of β = 30° with the horizontal axis . Point O represents the axis of rotation in the shoulder joint, point A represents the connection point of the deltoid muscle to the humerus, point B represents the center of gravity of the arm, and point C represents the application point of the force acting on the hand. The distances between the rotation axis (O point) of the shoulder joint and the points A, B and C are a=22 cm , b =33 cm and c= 60 cm , respectively . A force of F= 120 N, which makes an angle of γ=30° with the vertical from the point C, acts on the athlete's hand . Weight of the athlete's armW= 80 N. The direction of application of the Fm muscle force makes an angle of α=20° with the longitudinal axis of the arm. According to this; a) Calculate the muscle strength F M b) Calculate the angle θ of the joint reaction force F J with the horizontal.…4-6 if possible