Fe2O3(s) + 3H2(g) = 2Fe(s) + 3H2O(g) Part a: Use delta g values =frm a reference to calculate delta g for the reaction. =Delta G = 53 kj/mol Part b: Is this reaction spontaneous under standard conditions at 298k? Delta g is positie, so no. Part c: The value of Delta H for this reaction is 100.kj. At what temperature is this reaction spontaneous at standard conditions? Assume that delta H and delta S do not depend on temperatures? (So my question is how do u rearrange the formula ΔG=ΔH-TΔS to solve for the variable ΔS and also what is the answer for part c, i dont understand.
Fe2O3(s) + 3H2(g) = 2Fe(s) + 3H2O(g) Part a: Use delta g values =frm a reference to calculate delta g for the reaction. =Delta G = 53 kj/mol Part b: Is this reaction spontaneous under standard conditions at 298k? Delta g is positie, so no. Part c: The value of Delta H for this reaction is 100.kj. At what temperature is this reaction spontaneous at standard conditions? Assume that delta H and delta S do not depend on temperatures? (So my question is how do u rearrange the formula ΔG=ΔH-TΔS to solve for the variable ΔS and also what is the answer for part c, i dont understand.
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter10: Entropy And The Second Law Of Thermodynamics
Section: Chapter Questions
Problem 10.50PAE: For the reaction NO(g)+NO2(g)N2O3(g) , use tabulated thermodynamic data to calculate H and S. Then...
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Fe2O3(s) + 3H2(g) = 2Fe(s) + 3H2O(g)
Part a:
Use delta g values =frm a reference to calculate delta g for the reaction.
=Delta G = 53 kj/mol
Part b:
Is this reaction spontaneous under standard conditions at 298k?
Delta g is positie, so no.
Part c:
The value of Delta H for this reaction is 100.kj. At what temperature is this reaction spontaneous at standard conditions? Assume that delta H and delta S do not depend on temperatures?
(So my question is how do u rearrange the formula ΔG=ΔH-TΔS
to solve for the variable ΔS and also what is the answer for part c, i dont understand.
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