Learning Objective:Calculate the reaction yield in the presence of a limiting reagent.What you need: Pen and paperWhat to do: Analyze and answer the following questions by showing your solutions on aseparate sheet of paper.1. Consider the following chemical equation.a. How many moles of Fe304 can be obtained by reacting 16.8 g Fe with 10.0 g H2O?b. Which substance is the limiting reagent?c. Which substance is in excess?2. Aluminum (Al) reacts with chlorine gas (Cl2) to form aluminum chloride (A1C13) accordingto the balanced equation:In a certain experiment, 10.0 g of aluminum is reacted with 35.0 g of chlorine gas.a. How many moles of aluminum chloride would be produced in this complete reaction?b. Which substance is the limiting and excess reagent?c. How many moles of the excess reagent is left after the reaction?3. Nitric oxide (NO) reacts with oxygen gas to form nitrogen dioxide (NO2), a dark-brown gas:3 Fe(s) + 4 H20(g)Fes049) + 4 H2(g)2 Al(s) + 3 Cl2 (g)2 AlCl3 (s)2 NO(g)O22 NO2 (g)In one experiment 0.886 mole of NO is mixed with 0.503 mole of O2.a. Calculate the number of moles of NO2 produced.b. Determine the limiting and excess reagents.

Since you have asked multiple questions, we will solve the first question for you. If you want any…

Fes04(9) + 4 H2(G) 1. Consider the following chemical equation. 3 Fe(s) + 4 H2O(9) a. How many moles of Fe304 can be obtained by reacting 16.8 g Fe with 10.0 g H2O? b. Which substance is the limiting reagent? c. Which substance is in excess?

Fes04(9) + 4 H2(G) 1. Consider the following chemical equation. 3 Fe(s) + 4 H2O(9) a. How many moles of Fe304 can be obtained by reacting 16.8 g Fe with 10.0 g H2O? b. Which substance is the limiting reagent? c. Which substance is in excess?

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter6: Chemical Reactions: An Introduction

Section: Chapter Questions

Problem 68AP

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

Learning Objective:
Calculate the reaction yield in the presence of a limiting reagent.
What you need: Pen and paper
What to do: Analyze and answer the following questions by showing your solutions on a
separate sheet of paper.
1. Consider the following chemical equation.
a. How many moles of Fe304 can be obtained by reacting 16.8 g Fe with 10.0 g H2O?
b. Which substance is the limiting reagent?
c. Which substance is in excess?
2. Aluminum (Al) reacts with chlorine gas (Cl2) to form aluminum chloride (A1C13) according
to the balanced equation:
In a certain experiment, 10.0 g of aluminum is reacted with 35.0 g of chlorine gas.
a. How many moles of aluminum chloride would be produced in this complete reaction?
b. Which substance is the limiting and excess reagent?
c. How many moles of the excess reagent is left after the reaction?
3. Nitric oxide (NO) reacts with oxygen gas to form nitrogen dioxide (NO2), a dark-brown gas:
3 Fe(s) + 4 H20(g)
Fes049) + 4 H2(g)
2 Al(s) + 3 Cl2 (g)
2 AlCl3 (s)
2 NO(g)
O2
2 NO2 (g)
In one experiment 0.886 mole of NO is mixed with 0.503 mole of O2.
a. Calculate the number of moles of NO2 produced.
b. Determine the limiting and excess reagents.

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