Fill in the blanks to submit your answer to the following questions:(a) The lowest memory address associated with the 512KB RAM is.Write the complete 20-bit address in HEXADECIMALnotation without spaces. Note: For example, the lowest memory addressassociated with the RESERVED region is 0x00000 in HEXADECIMAL notation.(b) The highest memory address associated with the 512KB RAM is.Write the complete 20-bit address in HEXADECIMAL notation withoutspaces.(c) The memory-mapped IO address of the 1B Keyboard register is.Write the complete 20-bit address in HEXADECIMAL notation withoutspaces.(d) Say we utilize a DMUX8Way to route the load signal to the various regions ofthe memory in order to perform a data write. What would be the binary valuesof the DMUX8Way select bits needed in order to perform data write toSCREEN?Note: For example, if the select bits 2:0 were 011then you'd write Ob011 or 011 The regions of a 1 MB (Mega Byte) Memory are shown in the diagram below.Each memory register is 1B (Byte).The memory regions are as follows: 256 KB RESERVED, 512KB RAM, 128KBSCREEN, and 1B KEYBOARD. Their arrangement is shown in the diagram below.0RESERVEDRAMSCREENKEYBOARDUNUSED256 KB+4512 KB128 KB1 B

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Description: Fill in the blanks to submit your answer to the following questions:(a) The lowest memory address associated with the 512KB RAM is.Write the complete 20-bit address in HEXADECIMALnotation without spaces. Note: For example, the lowest memory addressa

Engineering

Computer Science

Fill in the blanks to submit your answer to the following questions: a) The lowest memory address associated with the 512KB RAM is - Write the complete 20-bit address in HEXADECIMAL notation without spaces. Note: For example, the lowest memory address associated with the RESERVED region is 0x00000 in HEXADECIMAL notation. b) The highest memory address associated with the 512KB RAM is .Write the complete 20-bit address in HEXADECIMAL notation without spaces. c) The memory-mapped 10 address of the 1B Keyboard register is spaces. - Write the complete 20-bit address in HEXADECIMAL notation without d) Say we utilize a DMUX8Way to route the load signal to the various regions of the memory in order to perform a data write. What would be the binary values of the DMUX8Way select bits needed in order to perform data write to SCREEN? Note: For example, if the select bits 2:0 were 011 then you'd write Ob011 or 011

Fill in the blanks to submit your answer to the following questions: a) The lowest memory address associated with the 512KB RAM is - Write the complete 20-bit address in HEXADECIMAL notation without spaces. Note: For example, the lowest memory address associated with the RESERVED region is 0x00000 in HEXADECIMAL notation. b) The highest memory address associated with the 512KB RAM is .Write the complete 20-bit address in HEXADECIMAL notation without spaces. c) The memory-mapped 10 address of the 1B Keyboard register is spaces. - Write the complete 20-bit address in HEXADECIMAL notation without d) Say we utilize a DMUX8Way to route the load signal to the various regions of the memory in order to perform a data write. What would be the binary values of the DMUX8Way select bits needed in order to perform data write to SCREEN? Note: For example, if the select bits 2:0 were 011 then you'd write Ob011 or 011

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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The memory unit of a computer has 1M words of 32 bits each. The computer has an instruction format with 4 fields: an opcode field; a mode field to specify 1 of 6 addressing modes; a register address field to specify one of 28 registers; and a memory address field. Assume an instruction is 32 bits long. Answer the following: a) How large must the mode field be? b) How large must the register field be? c) How large must the address field be? d) How large is the opcode field?
Suppose r0 = ox300010A0, r2 = 0x00000011, and the memory layout is as follows Address: Data: 0x300010A7 0x72 0x300010A6 0XA5 0x300010A5 0x9F 0x300010A4 0x00 0x300010A3 0x50 0x300010A2 0x2B 0x300010A1 0XA5 0x300010A0 0x01 -What is the Value of r0 and r1 after executing LDR r1, [r0, #2] -What are the values of r0 and r1 after executing the following code? Illustrate your process in a memory map. LDR r1, [r0], #3 ADD r1, r1, r2 STR r1, [r0, r#4]
Suppose r0 = ox300010A0, r2 = 0x00000011, and the memory layout is as follows Address: Data: 0x300010A7 0x72 0x300010A6 0XA5 0x300010A5 0x9F 0x300010A4 0x00 0x300010A3 0x50 0x300010A2 0x2B 0x300010A1 0XA5 0x300010A0 0x01 -What are the values of r0 and r1 after executing the following code? Illustrate your process in a memory map. LDR r1, [r0], #3 ADD r1, r1, r2 STR r1, [r0, r#4]
6. Suppose the RAM for a certain computer has 256M words, where each word is 32 bits long. a) What is the capacity of this memory expressed in bytes? b) If this RAM is byte addressable, how many bits must an address contain? c) If this RAM is word addressable, how many bits much an address contain?
The memory unit of a computer has 256K words of 32 bits each. The computer has an instruction format with four fields: an opcode field; a mode field to specify one of seven addressing modes; a register address field to specify one of 60 registers; and a memory address field. Assume an instruction is 32 bits long. Answer the following:Q.) How large must the address field be?
Computer Science This question is about paging-based virtual memory A computer has a virtual-momory space of 250MB (megabytes) The computer has 325) of primary memory. The pige som s-4000 by the address is 1011 0001 0101 1110 0010 1010 0010 a. How many frames can it have? b. Which of the bits in the virtual address correspond to the Page number? c. Which of the bits correspond to the page offset?
Part A For each byte sequence listed, determine the Y86 instruction sequence it encodes. If there is some invalid byte in the sequence, show the instruction sequence up to that point and indicate where the invalid value occurs. For each sequence, the starting address, then a colon, and then the byte sequence are shown. 0x100: 30f3fcfffff40630008000000000000 0x100: 30f3fcfffffff irmovq $-4,%rbx Ox10a: 40630008000000000000 | rrmovq %rsi,0×80A(%rcx) O0x115: 00 halt Ox100: 30f3fcffffffff irmovq $-4,%rbx Ox10a: 40630008000000000000 | rmmovq %rsi,0x800(%rbx) Ox114: 00 halt 0x100: 30f3fcfffffffff rrmovq $-8,%rbx Ox109: 40630008000000000000 | rmmovq %rsi,0x800(%rbx) 0x200: a06f800c020000000000000030f30a00000000000000 0x113: 00 halt 0x100: 30f3fcffffffffff irmovq $-4,%rbx 0x200: a06f pushq %rsi 0x10a: 40630008000000000000 | rmmovq %rsi,0x800(%rbx) Ox202: 800c02000000000000 call proc Ox116: 00 halt 0x20b: 00 halt 0x20c: proc: Submit Request Answer 0x20c: 30f30a00000000000000 | irmovq $10,%rbx…
Below is a list of 64-bit memory address references given as word address. Ox03, Oxb4, Ox2b, Ox01, Oxb7, Ox58, Oxbe, Ox02, Oxb5, Ox2e, Oxb6, Ox5b 0000 4 0100 8 1000 1100 1 0001 5 0101 9 1001 d 1101 2 0010 6 0110 a 1010 e 1110 3 0011 7 0111 b 1011 f 1111 Given a direct-mapped cache with 16 word blocks, what is the hit ratio? O 0.5 O 1 O 0.75 O 0.25
What precisely does the phrase "dynamic memory" refer to, and how does it differentiate itself from the term "static memory"?
The memory unit of a computer has 2M words of 32 bits each. The computer has an instruction format with 4 fields: an opcode field; a mode field to specify 1 of 4 addressing modes; a register address field to specify one of 9 registers; and a memory address field. Assume an instruction is 32 bits long. Answer the following: d) How large is the opcode field?
How is it that dynamic memory functions differently from regular memory?
A digital computer has a memory unit with 24 bits per word. The instruction set consists of 150 different operations. All instructions have an operation code part (opcode) and an address part (allowing for only one address). Each instruction is stored in one word of memory.Q.) What is the maximum allowable size for memory?