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Finally, use the Generalized Power Rule to determine[x -x], noting that x-x is the difference of two terms.

Finally, use the Generalized Power Rule to determine[x -x], noting that x-x is the difference of two terms.

Intermediate Algebra
Intermediate Algebra
19th Edition
ISBN:9780998625720
Author:Lynn Marecek
Publisher:Lynn Marecek
Chapter10: Exponential And Logarithmic Functions
Section: Chapter Questions
Problem 445RE: Mouse populations can double in 8 months (A=2A0) . How long will it take for a mouse population to...
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Finally, use the Generalized Power Rule to determine -[x⁹x], noting that x⁹ - x is the difference of two terms. d dx [(x − x)⁹] = 9(x² − x)³. dx = [x⁹-x] 9(x² − x)² · (d[x³] - 9(x² − x) ³ ( [ - - d dx d dx Therefore, if f(x) = (x⁹ − x)⁹, then we have the following result. f'(x) = [(x⁹. [(x d dx − x)] =
Transcribed Image Text:Finally, use the Generalized Power Rule to determine -[x⁹x], noting that x⁹ - x is the difference of two terms. d dx [(x − x)⁹] = 9(x² − x)³. dx = [x⁹-x] 9(x² − x)² · (d[x³] - 9(x² − x) ³ ( [ - - d dx d dx Therefore, if f(x) = (x⁹ − x)⁹, then we have the following result. f'(x) = [(x⁹. [(x d dx − x)] =
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