Find dy at taal dt and ya Vltx? and X = t.

Q: Can you help me with this problem step by step?

A: The given equation,

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A: Method of Variation of Parameters: This method is quite general and applies to equations of the form…

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A: We can solve the given problem using the chain rule of derivative.

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Q: dy dt t2

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A: Proceed as shown below....

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A: Consider the following function:        y=tanx finddydt when dxdt=3,x=π/4.

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Q: Find the derivative of y with respect to t. y=e(cos t+ln t) dy/dt=???

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A: To find the derivative of Y=ln(t^2) with respect to t.

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Q: Solve: dy + y² = ty dt

A: A differential equation is said to be Bernoulli's equation if the equation is of the form…

Q: If x = y3 - y and dy/dt = 5, then what is dx/dt when y = 2?

A: Given,

Q: Assume that y = 5x and dx/dt = 2. Find dy/dt.

A: Consider y = 5xApplying derivative with respect to t on both sides and plugging the values:

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A: Consider a function u(x) such that, Now, according to chain rule,  The given information is,

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A: the given function is: y=t3t3+26  we have to calculate dydt.

Q: dy Find at x = dt dx - 1 if y = 2x? – 3 and dt - 2. dy dt ||

A: y = 2x2 - 3dxdt = -2dydt = ?   at x=-1

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A: Given integral is

Q: 5) If y = x³ + 2.x and dx/dt = 5, find dy/dt when x = 2.

A: Q.5) If y=x3+2x and dxdt=5 Find: dydt when x=2

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Q: Assume that y=5x and dx/dt = 8 find dy/dt

A: Differentiate by chain rule : →f(g(x))dx = d(f(x))d(g(x))×d(g(x))dx.

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A: Solve the given

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Q: Find dy/dx. x = 9/t, , y = Vte-t

A: topic - derivative

Q: Assume that 2x + 3y = 12 and dy/dt = -2. Find dx/dt.

A: Assume,

Q: Find dy/dt. y =

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Q: Find the total differential. z = 10x y10 dz =

A: As we know that the: If the given function is z=fx,y then the expression for the total differential…

Q: Differentiate f(x) | Vt + sin t dt.

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Q: Find the total differential. z = 6x *y5 iz

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Q: Find dy/dx: 1. у%3D Jo = San* sec? t dt

A: A detailed solution is given below

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A: The parametric equations are given by x = 6t  y = te-1 To evaluate : The expression of dydx

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A: Given: xy+z2=z and dxdt=-1, dzdt=3  Find dydt when x=2 and z=4 differentiate  xy+z2=z with respect…

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Q: dy dt II

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Q: Find dy/dx by implicit differentiation. VTy = x'y +33 dy/dx =

A: The given equation is xy=x7y+33.