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- Given the zener voltage at 9V and the zener power at 1W, what is the range of allowable values of Iz (operating values). Choices: 0.11A 22mA to 89mA 9A 0.11A to 9A Plss show complete solutionDetermine the loop currents Ia, I,, and Ic. 100 Ic 100 100 100 100 Ib 55V 100 V laThe voltage across the resistor in series RL when suddenly supplied by a DC source is? a. zero O b. minimum O c. infinity O d. maximum
- When the voltage source is turned off in a simple circuit consists of a resistor and an inductor, the rate of decrease of the current is proportional to the current. The current is 40 amperes at the moment that the switch is off and dies down to 15 amperes after 0.01 sec. Determine the current in 0.02 sec. 3.375 amperes 4.25 amperes 5.625 amperes 6.025 amperesWhat is the current in the inductor ILO in continuity mode before opening the switch. R₁ Select one: O a. I = O b. I = E R₁ R₂ R₁+R₂ = E R₂ O c. I=0 O d. I E R₁ E k R₂ ILO LMay you explain part b a bit more I'm confused about how you got 2.5 after sin and e-j2.5
- R A IOLL 4) 2A A 2a R4 20V a) Find the voltage at point A due to the 20V source only. b) Find the voltage at point A due to the 2A current source only. c) Find the voltage at point A when both are activated.For some reason it's saying the 0.3636 is wrong. I tried 0.364 as well thinking it may be have wanted it rounded. This is explained very well. Thank you. On the second part, you did 60-60 because the charge didn't change. Is that correct?In the circuit in the figure, the amplitude of the input current is 5 Amps and its phase is 0 degrees, the amplitude of the input voltage is 18 volts and its phase is 90 degrees. How many volts is the amplitude of the voltage phasor V on capacitor C1? Values of the elements in the circuit:R= 14 OhmsC1= 10j OhmsC2= -3j OhmsL= 4j Ohms
- The first picture is the question the second pic i did not understand that step of %75 of the load means what ?Prob 2 Tihe switch in The Feg has been 3 kr A B 4ku in posit on A for a long tme, At t-o Hhe sWitch is moved o positi on B. Dete rmine vCE for t 70 and Calcalek its vakee at t=l and to 5ka 24V OSMF 30v t=45 v (1) = 30-1se Ans: } 'vc4)= 30-15 ē² .2 ; 27.97レChange the following normally open elements from the de-energized position to the energized position.