Find the electric field (magnitude and direction) at the location of qa in the figure below, given that q, = 10.70 µC and q. = -5.90 µC. Point charges located at the corners of an equilateral triangle 22.0 cm on a side. Magnitude |E| = direction (wrt +x-axis) = Submit Answer Incompatible units. No conversion found between "uc" and the required units. O Tries 0/10 Previous Tries What is the force (magnitude and direction) on qa, given that qa = 1.40 nC. Magnitude |F| = direction (wrt +x-axis) = Submit Answer Tries 0/10

Find the electric field (magnitude and direction) at the location of qa in the figure below, given that q, = 10.70 µC and q. = -5.90 µC. Point charges located at the corners of an equilateral triangle 22.0 cm on a side. Magnitude |E| = direction (wrt +x-axis) = Submit Answer Incompatible units. No conversion found between "uc" and the required units. O Tries 0/10 Previous Tries What is the force (magnitude and direction) on qa, given that qa = 1.40 nC. Magnitude |F| = direction (wrt +x-axis) = Submit Answer Tries 0/10

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter5: Electric Charges And Fields

Section: Chapter Questions

Problem 52P: Suppose Earth and the Moon each carried a net negative charge Q . Approximate both bodies as point...

See similar textbooks

Similar questions

Find the electric field at the origin due to three charges: q1 = 1 nC is at (x, y) = (-3, 0)m q1 = 1 nC is at (x, y) = (4, 0)m q1 = -8 nC is at (x, y) = (12,0)m Assume a precision of 3 significant figures for all parameters. Give your answer in N/C. A positive answer would indicate an electric field in the positive 'x' direction, and a negative answer would indicate an electric field in the negative 'x' direction
q1 = (8.60x10^-9) C q2 = (1.232x10^-8) C x = (6.060x10^1) m d = (3.3000x10^0) m Find the Electric Field at point P due to q1 and q2 for this set up.If the field is to the left, include a negative sign to indicate this. Your answer should include:3 significant figuresUnits with your answer
Two charges q1 = +2.27 μC and q2 = +8.2 μC are separated by a distance of 19.49 cm. Point P is locatedalong the line segment joining the two charges. How far is P (in cm) from q1, if the magnitude of the electricfield at P due to the two charges is equal to zero? Express your answers accurate to two decimal places.Draw a sketch of the problem and label appropriately.
The electric field vector is given by E=[0.2, –0.6, 0.3] V/m and Area vector points to A=[–4, 3, -5] m^2. What is the angle between the E-field and Area vector in degrees? Answer with two decimal places. note: convert answer to milli
Two charges lie in a line along the x axis. Charge 1 is q1 = 1.1 C and charge 2 is q2 = 2.15 C. They are each a distance of d = 0.093 m from the origin. a)What is the distance on the x-axis from the origin at which the electric field will be zero. Give your answer in meters.
Q. 13 : A charged conductor has an area of 1 m² and charge of V8.85 µC. The force acting on (CET-2002) unit area of the conductor is
A parallel plate capacitor has a surface charge density of σ = 0.0046 C/m2 on one plate. A small sphere charged to Q = 5.2E-06 C is moved a distance d = 0.17 m between the plates. Refer to the figure, which is not drawn to scale. Enter an expression for the electric field vector within the capacitor, E, using given quantities and the unit vectors i and j.
Pls help me asap with the following and make sure its correct 100%, thanks Q: Answer the given question. 1. Three +4.0 nCnC charges are positioned at the points (-1 mm, 0), (1 mm, 0), and (0, 2 mm). What is the magnitude of the electric field at the origin? Express your answer with the appropriate units.
Consider the following. 60.0⁰ 0.500 mm (a) Red blood cells often become charged and can be treated as point charges. Healthy red blood cells are negatively charged, but unhealthy cells (due to the presence of a bacteria, for example) can become positively charged. In the figure, three red blood cells are oriented such that they are located on the corners of an equilateral triangle. The red blood cell charges are A = 1.80 pC, B = 7.10 pC, and C = -4.80 pC. Given these charges, what would the magnitude and direction of the electric field be at cell A? (1 pC = 1 x 10-12 C.) magnitude N/C direction counterclockwise from the +x-axis (b) If the charge of cell A were doubled, how would the electric field at cell A change? O The field would be unchanged. O The magnitude of the field would be doubled. O The magnitude of the field would be halved. O The magnitude of the field would be quadrupled.
The coordinate of charge q1=20μC is P1 (10,6) , the coordinate of charge q2=17μC is P2 (7,6) and the coordinate of charge q3=12μC is P3 (3,9). The coordinates have centimeters as unit. a)Find the vector pointing from q1 to q2. This vector is denoted by r. b) x and y component of r.
At what distance from a particle with a charge of 3.00 nC does the electric field of that charge have a magnitude of 6 N/C? The distance = Answer m
92 93 di – dz- Three point charges lie along a straight line as shown in the figure below, where q1 = 6.81 µC, q2 = 3.72 µC, and q3 = - 9.49 µC. The separation distances are d1 = 6.21 cm and d2 = 2.18 cm. Calculate the magnitude of the net electric force on q1. %3D %3D Round your answer to have 1 decimal place. Your Answer: Answer