Find the toughness for a metal that experience valid for elastic deformation, that the modulu terminates at a strain of 0.007. For plastic defor strain is a = Ke, in which the values for Ka plastic deformation c
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- Find the total toughness energy for a metal that experiences both elastic and plastic deformations. The modulus of elasticity is 107.2 GPa, and elastic deformation terminates at a strain of 0.009. For plastic deformation, assume that the relationship between stress and strain is described by T = 1.66xKn, in which the values for K and n are 1453 MPa and 0.175, respectively. Furthermore, plastic deformation occurs between strain values of 0.009 and 0.67, at which point fracture occursA 8mm diameter rod, of unknown material, is subjected to 50kN tensile load. In the process, its length increased from 300mm to 303mm. If the stress is proportional to strain, determine the modulus of elasticity, in GPa. of the material?(d) Figure Q2 (d) shows a typical aluminum stress-strain curve. A mechanical engineer has to carry out a tensile test for a rod of aluminum that can withstand an applied force of 20kN. To ensure safety, the maximum allowable stress on the rod is limited to 400 MPa, which is below the yield strength of the aluminum. The rod must be at least 380 cm long and must deform elastically not more than 0.8 cm when the force is applied. Design the appropriate rod.
- In our previous topic regarding strain, repeat the problem on the strain using thefollowing parameters:F = 150000 +/- 150 lbfSide length = 1.2 +/- 0.025 inModulus of Elasticity = 25000 +/- 11.5 ksiDetermine the relative error. Is it above or below the accepted 5% error?Use the engineering stress strain diagram provided below to answer parts (A) to (H) below (the stress-strain diagram bas already been drawn for you): stress strain diagram 400 350 0 300 0 250 0 200 0 150.0 100.0 50.0 O 05 0 1 0.15 strain A. Determine the tensile strength of this alloy. B. show the elastic, plastic and total strain on the diagram stress (Mpa)Determine the tensile yield strength (0.2% offset) and the maximum strength of a metal alloy having the following tensile stress-strain diagram. 600 500 400 500 300 400 300E 200 3200 100 100E 0.000 0.002 0.004 0.006 Strain ol 0.00 0.16 0.20 0.08 Strain 0.04 0.12 Select one: O The tensile yield strength Sy = 290 Mpa and the maximum strength Smax = 500 Mpa. O The tensile yield strength Sy = 170 Mpa and the maximum strength Smax = 400 Mca. G The tensile yield strength Sy = 200 Mpa and the maximum strength Smax = 500 Moa. O Tne tensile yield strength Sy = 390 Mpa and the maximum strength Smax= 500 Mpa. The tensile yed strength Sy = 150 Mpa and the maximum strength Smax = 250 Mpa. Stress (MPa) Stress (MPa)
- 3. Find the young's modulus of a bars a rod of diameter 25 mm and of length 250 mm which is subjected to a tensile load of 50 kN when the extension of the rod is equal to 0.3 mm. And if the modulus of elasticity of the material of the rod is 2x105 N/mm² determine stress, strain and % elongation of the rod.2. An elastic rod of 25mm in diameter, 200mm long extends by 0.25mm under a tensile load of 40kN. Find the intensity of stress, the strain and the elastic modulus for the material of the rod.A material has a linear elastic perfectly plastic stress-strain. A cylindrical specimen of that material having an initial length of 35 mm and a tadius of 7 mm is pulled until it elongates 0.8mm. a. Calculate the stain and the corresponding stress at that elongation value. b. Afterward, the specimen is released to zero stress level, how does the final length of the specimen compare with its original length? How much plastic deformation remains if it exists?
- The figure below shows the tensile engineering stress-strain behavior for a steel alloy. (a) What is the modulus of elasticity? (b) What is the yield strength at a strain offset of 0.002? (c) What is the tensile strength? Stress (MPa) 600 500 400 300 200 100 T I 0.00 Stress (MPa) 0.04 500 400 300 200 100 0.000 0.08 0.002 Strain 0.004 Strain 0.12 I 0.006 0.16 0.20 In the previous problem, A load of 85,000 N (19,100 lbf) is applied to a cylindrical specimen of the steel alloy that has a cross-sectional diameter of 15 mm (0.59 in.). (a) Will the specimen experience elastic and/or plastic deformation? Why? (b) If the original specimen length is 250 mm (10 in.), how much will it increase in length when this load is applied?Experiments were conducted in a tension testing machine to evaluate the material properties of two metallic rods both having diameter equal to 10 mm. First rod having modulus of rigidity of the material equal to 400 tonnes/cm2 when subjected to an axial tensile force of 6 kN, the change in its diameter was observed to be 0.0018 cm. The value for the bulk modulus of the second metallic rod is same as that of the first one but modulus of elasticity 18% more. Based on the material properties calculate and compare the values of different moduli as well as Poisson’s ratio for both metallic rods. Justify your answer with reasons.3. A cylindrical specimen of a metal alloy 10 mm in diameter is stressed elastically in tension. A force of 3370 Ibr produces a reduction in specimen diameter of 7 x 103 mm. Compute Poisson's ratio for this material if its elastic modulus is 100 GPa. 4. A cylindrical specimen of a hypothetical metal alloy is stressed in compression. If its original and final diameters are 20.000 and 20.025 mm, respectively, and its final length is 74.96 mm, compute its original length if the deformation is totally elastic. The elastic and shear moduli for this alloy are 105 GPa and 39.7 GPa, respectively.