// Finds all duplicate elements in the array. for (int i = 1; i <= arrSize; i++) { for (int j = i+1; j <= arrSize; j++) { // if a duplicate is found then increment counter by if (arr[i] == arr[j]) { totalNumofDuplicates++; hreak:

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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What is the time complexity of this algorithm? It has an IF statement within a nested FOR loop. 

// Finds all duplicate elements in the array.
for (int i = 1; i <= arrSize; i++)
for (int j
{
// if a duplicate is found then increment counter by 1.
if (arr[i]
{
totalNumofDuplicates++;
break;
i+1; j
arrSize; j++)
arrlj])
==
Transcribed Image Text:// Finds all duplicate elements in the array. for (int i = 1; i <= arrSize; i++) for (int j { // if a duplicate is found then increment counter by 1. if (arr[i] { totalNumofDuplicates++; break; i+1; j arrSize; j++) arrlj]) ==
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