Fix this error. In row I need remember.
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- IntSet unionWith(const IntSet& otherIntSet) const; //Unions the current set with the passed set. IntSet::unionWith(const IntSet& otherIntSet){ for (int i = 0; i < otherIntSet.used; ++i) //For each element in the passed set. { add(otherIntSet.data[i]); //Add it to current set. }}Direction: Continue the code below and add case 4, case 5, and case 6. Add 3 more functions aside from insert, getValue, and clear from List ADT import java.util.LinkedList; import java.util.Scanner; class SampleLL { } public static void main(String[] args) { LinkedList 11s = new LinkedList(); String msg = "Choose a function: \n [1] Insert, [2]Get Value, [3]Clear, [0] Exit"; System.out.println(msg); Scanner scan= new Scanner(System.in); int choice scan.nextInt (); while(true) { } if (choice =0) { } System.exit(0); switch(choice) { } case 1: System.out.println("Enter a word/symbol:"); break; case 2: System.out.println("Enter a number: "); break; 11s.add(scan.next()); break; case 3 11s.clear(); default: System.out.println("Invalid input!"); break; System.out.println(11s.get (scan.nextInt())); System.out.println(msg); choice scan.nextInt ();Write a Python code using the given function and conditions. Do not use Numpy. Use LinkedList Manipulation. Given function: def insert(self, newElement, index) Pre-condition: The list is not empty. Post-condition: This method inserts newElement at the given index of the list. If an element with the same key as newElement value already exists in the list, then it concludes the key already exists and does not insert the key. [You must also check the validity of the index].
- // MergeSortTest.java// Sorting an array with merge sort.import java.security.SecureRandom;import java.util.Arrays; public class MergeSortTest { // calls recursive sortArray method to begin merge sorting public static void mergeSort(int[] data) { sortArray(data, 0, data.length - 1); // sort entire array } // splits array, sorts subarrays and merges subarrays into sorted array private static void sortArray(int[] data, int low, int high) { // test base case; size of array equals 1 if ((high - low) >= 1) { // if not base case int middle1 = (low + high) / 2; // calculate middle of array int middle2 = middle1 + 1; // calculate next element over // split array in half; sort each half (recursive calls) sortArray(data, low, middle1); // first half of array sortArray(data, middle2, high); // second half of array // merge two sorted arrays after split calls…Using Java write a method, reverse(), that reverses the order of elements in a DLList#The Iris Dataset import sklearn.datasetsimport matplotlib.pyplot as plt import numpy as np import scipy iris = sklearn.datasets.load_iris() Write a function that takes in an index i and prints out a verbose desciption of the species and measurements for data point i. For example:Data point 5 is of the species setosaIts sepal length (cm) is 5.4Its sepal width (cm) is 3.9Its petal length (cm) is 1.7Its petal width (cm) is 0.4
- def makeRandomList(size): lyst = [] for count in range(size): while True: number = random.randint(1, size) if not number in lyst: lyst.append(number) break return lyst give me proper analysis of this code and Big OJava program with implementation of list using array Using switch, the user should be able to: It can add an item It can print the list It can get the size of the list It can edit an item It can delete an itemData Structure and algorithms ( in Java ) Please solve it urgent basis: Make a programe in Java with complete comments detail and attach outputs image: Question is inside the image also: a). Write a function to insert elements in the sorted manner in the linked list. This means that the elements of the list will always be in ascending order, whenever you insert the data. For example, After calling insert method with the given data your list should be as follows: Insert 50 List:- 50 Insert 40 List:- 40 50 Insert 25 List:- 25 40 50 Insert 35 List:- 25 35 40 50 Insert 40 List:- 25 35 40 40 50 Insert 70 List:- 25 35 40 50 70 b). Write a program…
- def update_messages (msgs: List [str], lens: List [int]) -> None: ""Update the list of the strings in msgs so their lengths are adjusted to match the value at the corresponding position in lens. Strings that are too long should be shortened by leaving off characters at the end and strings that are too short should be lengthened by adding underscores to the end. Precondition: len (msgs) == len(lens) and all values in lens are >= 0 ['aardvark', 'bear', 'cat', 'dog'] >>> update_messages (messages, [6, 5, 5, 3]) >>> messages = >>> messages ['aardva', 'bear_', 'cat__', 'dog'] >>> messages = ['', 'cat'] >> update_messages (messages, [3, 0]) >>> messages ['---', '']Question 1 If N represents the number of elements in the collection, then the add method of the SortedArrayCollection class is O(N). True False Question 2 If N represents the number of elements in the list, then the index-based remove method of the ABList class is O(N). True False Question 3 The add method of our Collection ADT might throw the CollectionOverflowException. True False Question 4 A list allows retrieval of information based on the size of the information. True False Question 5 Our CollectionInterface defines a single constructor. True False Question 6 Our lists allow null elements. True False Question 7 Even though our collections will be generic, our CollectionInterface is not generic. True False Question 8 Our lists are unbounded. True False Question 9 If N represents the number of elements in the collection, then the contains method of the ArrayCollection class is O(N). True False Question 10 Our lists allow duplicate elements. True False3. void insert (Node newElement) or def insert(self, newElement) (4) Pre-condition: None. Post-condition: This method inserts newElement at the tail of the list. If an element with the same key as newElement already exists in the list, then it concludes the key already exists and does not insert the key.