For a colony of 10,000 persons having sewage flow rate of 200 1/capita/day, BOD of applied sewage is 300 mg/l and organic loading rate is 3000 kg/day/hectare. Find the area of an oxidation pond (in m2) required for treating the sewage of the colony.

For a colony of 10,000 persons having sewage flow rate of 200 1/capita/day, BOD of applied sewage is 300 mg/l and organic loading rate is 3000 kg/day/hectare. Find the area of an oxidation pond (in m2) required for treating the sewage of the colony.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

(a) Design an oxidation pond for treating sewage from a hot climatic residential colony with 4000 persons, contributing sewage @ 180 lped. The 5-day BOD of sewage is 350 mg/L. Assume organic loading = 300 kg/ha/day Length to breadth ratio = 2:1 Effective depth = 1.2 m Average velocity of sewage in pipe = 1 m/s Daily flow of sewage to oxidation pond for 8 hours only Diameter of outlet pipe = 1.5 times that of the inlet pipe P
Problem 2.Assume that DLSUD lake is 100m² and its average height is 5ft. Wastewater that flows into the lake are the following: a. Food square kitchen waste 5m³/hr; Total Dissolved Solids (TDS) is 50g/L_which operates 8hrs per day b. CIH 5m³/hr kitchen waste; TDS is 20mg/L which operates 4hrs per day c. PCH 20m/day diluted laboratory waste ; TDS = 40mg/L (1)Determine the volume of wastewater which DLSUD lake can still be contained without rainfall. (2)During operational hours a heavy rain fall, the rain gauge reading is 1.5m. Will the DLSUD Lake overflow? What is the volume of water that will over flow? (3). Compute the TDS concentration of the overflow.
Questions 1. Explain factors affecting self purification of natural streams. 2. What is reoxygenation? What are the factors that affect reoxygenation? 3. Derive Streeter-Phelps equation for oxygen sag analysis. 4. A river is having discharge of 22 m³/s receives wastewater discharge of 5 m³/s. The initial DO of the river water is 6.3 mg/L, and DO content in the wastewater is 0.6 mg/L. The five day BOD in the river water is 3 mg/L, and the wastewater added to river has five day BOD of 130 mg/L. Consider saturation DO of 8.22 mg/L and deoxygenation and reoygenation constant values of 0.1 and 0.3 per day, respectively. Find critical DO deficit and DO in the river after one day. The average velocity of flow in the stream after mixing of wastewater is 0.18 m/sec. A municipal wastewater treatment plant discharges secondary effluent to a river. The worst condition occurs in the summer when the treated wastewater in summer is found to have a maximum flow rate of 10000 m³/day, a BOD, of 30 mg/L,…
Problem 2.Assume that DLSUD lake is 100m? and its average height is 5ft. Wastewater that flows into the lake are the following: Food square kitchen waste 5m³/hr; Total Dissolved Solids (TDS) is 50g/L which operates 8hrs per day b. CIH 5m³/hr kitchen waste; TDS is 20mg/L which operates 4hrs per day c. PCH 20m³/day diluted laboratory waste ; TDS = 40mg/L а. (1)Determine the volume of wastewater which DLSUD lake can still be contained without rainfall. (2)During operational hours a heavy rain fall, the rain gauge reading is 1.5m. Will the DLSUD Lake overflow? What is the volume of water that will over flow? (3). Compute the TDS concentration of the overflow.
For a colony of 10000 persons having sewage flow rate of 200 1/capita/day, BOD of applied sewage is 300 mg/1 and organic loading rate is 300 kg/day/hectare. The area of an oxidation pond required for treating the sewage of the colony is hectare.
i). A town produces 8 million litre of sewage per day. BOD of sewage is 260 mg/L, it is to be discharged into a river flowing at a rate of 0.2 m³/s and it's BOD is 5 mg/L. Find out the BOD of river after mixing? [Assume mixing is instantaneous]
A township is to treat 5,00,000 litres of sewage per day which has a 5-days BOD of 150 ppm. An oxidation pond is used for the purpose. The effluent can have a BOD of 15 ppm. The loading is to be 40 kg of 5-days BOD per hectare per day. The required area of the pond is
Assume that DLSUD lake is 100m2 and its average height is 5ft. Wastewater that flows into the lake are the following: Food square kitchen waste 7 m3/sec; Total Dissolved Solids (TDS) is 25,000 mg/L which operates 8hrs per day CIH 5m3 /hr kitchen waste; TDS is 20mg/L which operates 4hrs per day PCH 20m3 /day diluted laboratory waste ; TDS = 40mg/L (1)Determine the volumetric flow rate of the lake water can still accommodate prior to rainfall.
The treated domestic sewage of a town is to be discharged in the natural stream in which minimum flow is equal to 0.14 m³/s. The BOD in the stream on the upstream side is 3 mg/L. The treatment plant receives the waste water from a town with a population of 60000 persons with a dry weather flow of ( 153 liters/capita/day. Assume per capita BOD contribution as 0.07 kg/day. a) Determine the percentage of the purification required in the treatment plant if the permissible BOD on the downstream side of the stream is 5 mg/L. b) Draw a labeled diagram to show the process of self-purification of the natural stream if it receives the treated effluent.
The treated domestic sewage of a town is to be discharged in a natural stream with following data given: (i) Population = 50,000 (ii) BOD contribution per capita = 0.07 kg/day (iii) BOD of stream on u/s side = 3 mg/It. (iv) Permissible maximum BOD of stream on d/s side = 51 (v) Dry weather flow of sewage = 140 litres per capita per day 5 mg/lt. (vi) Minimum flow of stream = 0.13 m3/sec Choose the correct statement(s): BOD of treated sewage should be 8.21 gm/lt. Total BOD produced per day is 35000 kg/day C BOD of untreated sewage is 500 mg/It. Correct Option D Percentage treatment required is 98.358% Correct Option
Design an oxidation pond to treat waste water from a community of 10,000 people with a per capita BOD contribution of 40 grams/day. Water is supplied at a rate of 100 Ipcd and 80% of this is converted to sewage. Determine the detention time and also whether the effluent is suitable for irrigation if 80% BOD removal is achieved in the pond. (d) the permissible BOD loading rate to oxidation pond is 200 kg BOD/hectare Assume : (a) pond's length to width ratio 4 : 1 (b) depth of the pond is 2 m (c) permissible BOD < 100 mg/L for irrigation water, and 46
Q- If the average sewage from a city is 40×106 l/day and the average 5-day BOD is 200 mg/l against a standard of 80 mg/day per capita at 20°C, then what will be the population equivalent of the city.