For a soil specimen, given the following: % passing sieve #4 -92%, sieve #10-81%, sieve # 40-78%, LL-48%, PL=16%, GI-18.2 classify the soil by AASHTO classification system. GI = (F 200 - 35)[0.2 + 0.005(LL - 40)] +0.01 (F200 - 15) (PI - 10)
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- For a soil specimen, the following are given: % passing Sieve No. 4 = 92% % passing Sieve No. 10 = 81% % passing Sieve No. 40 = 78% % passing Sieve No. 200 = 65% LL = 48% PI = 32% Classify the soil by the AASHTO system. O A-2-7 (15) O A-7-6 (18) O A-7-6 (32) O A-2-5 (6)The results of the particle-size analysis of the soil are as follows: Percent passing No. 10 sieve = 100; Percent passing No. 40 sieve = 80; Percent passing No. 10 sieve = 58.The LL and PI of minus No. 40 fraction of the soil are 30 and 10 respectively. Classify the soil by USCS system a. CH b. SP-SC c. CL-ML d. CL-MLPROBLEM 7: The laboratory results of a soil test are as follows: Sieve No. # 4 #10 #40 #200 LL PL Percent passing 100 93.20 81 55 45 17 Find the group index according to AASHTO classification system. Hint: GI = (F-35)[0.20 + 0.005(LL – 40)] + 0.01(F – 15)(PI – 10)
- Sr B. ( A Soil Specimen has the following characteristics: % passing No.4 sieve = 85 % passing No.200 sieve = 11 D60 = 2 mm D30=0.35 mm D₁0 = 70 μm D8=2 μm L.L = 36% P.L = 31% 1. Classify the specimen according to the Unified Soil Classification System (USCS). Assign the group name and the group symbol. 2. Determine the soil activity. 3. Determine the soil Liquidity index and consistency index if wc = 26%.B. ( A Soil Specimen has the following characteristics: % passing No.4 sieve = 85 % passing No.200 sieve = 11 D60 = 2 mm D30 = 0.35 mm D10 = 70 μm L.L = 36% P.L = 31% D8 = 2 μm 1. Classify the specimen according to the Unified Soil Classification System (USCS). Assign the group name and the group symbol. 2. Determine the soil activity. 3. Determine the soil Liquidity index and consistency index if we = 26%. JQ5) A: Laboratory test results on the soil (L.L=35% and P.L-21%) is given in the following Table below. Classify the soil by using the unified classification system (10 mark) (showing all steps). Sieve Size(mm) Weight retained (gm) 4.75 2 0.425 0.25 0.075 Pan 135 70 60 30 142.5 462.5 B: A fine-grained soil has a liquid limit of 200% and a plastic limit of 45%, The natural water content of the soil in the field is 60% and the clay content is 63%, Calculate the plasticity index, the liquidity index and the activity. (10 mark)
- A The results of the particle-size analysis of the soil are as follows: Percent passing No. 10 sieve = 100; Percent passing No. 40 sieve = 80; Percent passing No. 10 sieve = 58. The LL and PI of minus No. 40 fraction of the soil are 30 and 10 respectively. Classify the soil by AASHTO system.Justify your answer. provide fbd a.A-6 (5) b.A-5 (6) c.A-4 (5) d.A-7-6 (20)A sample of soil was tested in the laboratory, and the test results were listed as follows. Classify the soil by both the AASHTO and the USCS. - LL = 29%, PL = 19% Sieve Size 1 in 3/4 in 3/8 in #4 #10 #40 #200 Percent Passing 100 90 82 70 65 54 25Classify the soil sample using AASHTO Classification System. Passing No. 10 = 89 % Passing No. 40 = 64 % Passing No. 200 = 48 % Plasticity for the minus No. 40 fraction: Liquid Limit = 36 % Plastic Limit = 27 % O GI = 2.0 O A-6 (2) O A-5 (0) O A-4 (2) O A-7-5 (0) O GI = 1.0 O GI = 0
- Q.2 Results of sieve analysis are shown in the table below. Check whether this soil can be classified as SP or not? 100 90 60 30 10 3. Finer (%) No. 200 No. 4 3 mm 0.42 mm 0.25 (0.075 *Sieve 12.5 mm (4.7 mm) mm)• Problem 4- A soil sample from a certain excavation has the following grain size characteristics; Sieve size (mm) 2.00 0.075 0.500 0.005 0.002 % Finer 100 80 64 35 20 The group index of the soil was 17 and has a plasticity index of 24. Determine the liquid limit of the soil. GI = (F-35) [0.2 +0.005(LL-40)] +0.01 (F-15) (P.I. - 10)Sieve and Atterberg limits tests were made on a soil specimen and th results are given below: Sieve No. Wt. of sieve (gm) Wt. of sieve + Soil (gm) 1" 450 518 378 420 L.L = 32% 4 100 370 425 PL = 17% 365 200 442 W₂ = 21% 485 Pan 793 D15 = 0.002 1. Classify the specimen according to the Unified Soil Classification System (USCS). Assign the group name and the group symbol. 2. Determine the soil activity. in the soil Liquidity index and consistency index