For a solution in which u = 8.0 x 10, calculate K', for s. Pbl,. The thermodynamic constant of the solubility -9 constant of Pbl, is 7.9 x 10. Use the linear interpolation of experimental data below. TABLE 10-2 Activity Coefficients for Ions at 25°C Activity Coefficient at Indicated lonic Strength lon 0.001 0.005 0.01 0.05 0.1 H,O L. CH,CO0 Na". 10,, HSO,. HCO,. H,PO,. HASO, OAC OH,F. SCN, HS", CIO,. CIO,. HrO,. 10,, MnO, K*. Cr, Br,I, CN", NO,, NO,. HCOO- Rb", C. TI'. Ag". NH," Mg*, Be G.. Za". Sa". Ma". Fe", Ni", Co". Phchalate St, Ba", Cd", Hg", s P, Co,. So,.CO He", so,", S,0,", Cr", HPO, AP. Fe. C, La, Ce PO,. Fe(CN), Th, Z, Ce, Sn* Fe(CN), 0.85 0.83 0.9 0.967 0.934 0.913 0.83 0.6 0.966 0.930 0.907 0.80 0.4-0.45 0.965 0.927 0.902 0.82 0.77 0.926 0.925 0.76 0.75 0.35 0.965 0.900 0.81 0.899 0.897 0.3 0.965 0.81 0.25 0.965 0.925 0.80 0.75 0.8 0.872 0.756 0.690 0.52 0.44 0.6 0.870 0.748 0.676 0.48 0.40 0.743 0.741 0.5 0.869 0.668 0.46 0.38 0.45 0.868 0.665 0.45 0.36 0.40 0.867 0.738 0.661 0.44 0.35 0.9 0.737 0.540 0.443 0.24 0.18 0.4 0.726 0.505 0.394 0.16 0.095 0.063 1.1 0.587 0.569 0.348 0.252 0.10 0.5 0.305 0.200 0.047 0.020 Source Reprinted tadapted) with permision from J. Kielland. I Am. Chem. Sac, 1937, 59, 1675, DOI 10.1021/ja01288a2. Cepyright 1937 Ametican Chemical Society
For a solution in which u = 8.0 x 10, calculate K', for s. Pbl,. The thermodynamic constant of the solubility -9 constant of Pbl, is 7.9 x 10. Use the linear interpolation of experimental data below. TABLE 10-2 Activity Coefficients for Ions at 25°C Activity Coefficient at Indicated lonic Strength lon 0.001 0.005 0.01 0.05 0.1 H,O L. CH,CO0 Na". 10,, HSO,. HCO,. H,PO,. HASO, OAC OH,F. SCN, HS", CIO,. CIO,. HrO,. 10,, MnO, K*. Cr, Br,I, CN", NO,, NO,. HCOO- Rb", C. TI'. Ag". NH," Mg*, Be G.. Za". Sa". Ma". Fe", Ni", Co". Phchalate St, Ba", Cd", Hg", s P, Co,. So,.CO He", so,", S,0,", Cr", HPO, AP. Fe. C, La, Ce PO,. Fe(CN), Th, Z, Ce, Sn* Fe(CN), 0.85 0.83 0.9 0.967 0.934 0.913 0.83 0.6 0.966 0.930 0.907 0.80 0.4-0.45 0.965 0.927 0.902 0.82 0.77 0.926 0.925 0.76 0.75 0.35 0.965 0.900 0.81 0.899 0.897 0.3 0.965 0.81 0.25 0.965 0.925 0.80 0.75 0.8 0.872 0.756 0.690 0.52 0.44 0.6 0.870 0.748 0.676 0.48 0.40 0.743 0.741 0.5 0.869 0.668 0.46 0.38 0.45 0.868 0.665 0.45 0.36 0.40 0.867 0.738 0.661 0.44 0.35 0.9 0.737 0.540 0.443 0.24 0.18 0.4 0.726 0.505 0.394 0.16 0.095 0.063 1.1 0.587 0.569 0.348 0.252 0.10 0.5 0.305 0.200 0.047 0.020 Source Reprinted tadapted) with permision from J. Kielland. I Am. Chem. Sac, 1937, 59, 1675, DOI 10.1021/ja01288a2. Cepyright 1937 Ametican Chemical Society
Chapter7: Statistical Data Treatment And Evaluation
Section: Chapter Questions
Problem 7.26QAP
Related questions
Question
100%
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you