For finding the oxidation state of metal atom in coordination compound, charge on the ligand should be known. Chloro ligand has -1 charge. amino ligand is neutral. [MnCl2(NH3)41* Let x is the oxidation state of metal. Above compound has +1 charge on it x+2(-1)+4(0) = 1 x - 2+0 = 1 x=1+2= 3 So, oxidation of Mn metal = 3 (Co(CN)4(H20)2]2- x+4(-1) + 2(0) = -2 x= -2 + 4 = 2 Oxidation state of Co metal = 2 [Fe(OH)sCO]3- x+ 5(-1) +0 = -3 x - 5 = -3 x = -3 +5= 2 So, oxidation state of Fe metal = 2
For finding the oxidation state of metal atom in coordination compound, charge on the ligand should be known. Chloro ligand has -1 charge. amino ligand is neutral. [MnCl2(NH3)41* Let x is the oxidation state of metal. Above compound has +1 charge on it x+2(-1)+4(0) = 1 x - 2+0 = 1 x=1+2= 3 So, oxidation of Mn metal = 3 (Co(CN)4(H20)2]2- x+4(-1) + 2(0) = -2 x= -2 + 4 = 2 Oxidation state of Co metal = 2 [Fe(OH)sCO]3- x+ 5(-1) +0 = -3 x - 5 = -3 x = -3 +5= 2 So, oxidation state of Fe metal = 2
Chapter21: Transition Metals And Coordination Chemistry
Section: Chapter Questions
Problem 2RQ
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![For finding the oxidation state of metal atom in coordination compound, charge on the ligand should be known.
Chloro ligand has -1 charge. amino ligand is neutral.
[MnCl2(NH3)4]*
Let x is the oxidation state of metal. Above compound has +1 charge on it
x+2(-1)+4(0) = 1
x-2+0=1
x =1+2= 3
So, oxidation of Mn metal = 3
[Co(CN)4(H20)2]²-
x+ 4(-1) + 2(0) = -2
x= -2 +4 = 2
Oxidation state of Co metal = 2
[Fe(OH)sCO]3-
x+5(-1) + 0 = -3
x - 5 = -3
x= -3 +5= 2
So, oxidation state of Fe metal = 2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3b2b4ef7-96ed-417d-8c9f-a6799cd31caf%2Fd06bf37d-516f-44ac-bcd4-068ab8a978e9%2F80o82np_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For finding the oxidation state of metal atom in coordination compound, charge on the ligand should be known.
Chloro ligand has -1 charge. amino ligand is neutral.
[MnCl2(NH3)4]*
Let x is the oxidation state of metal. Above compound has +1 charge on it
x+2(-1)+4(0) = 1
x-2+0=1
x =1+2= 3
So, oxidation of Mn metal = 3
[Co(CN)4(H20)2]²-
x+ 4(-1) + 2(0) = -2
x= -2 +4 = 2
Oxidation state of Co metal = 2
[Fe(OH)sCO]3-
x+5(-1) + 0 = -3
x - 5 = -3
x= -3 +5= 2
So, oxidation state of Fe metal = 2
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