For R1=9, R2=1, R3=1, R4=1 and 15-13.5 A in the shown circuit, use current divider to find the following: 15 i1 (in Ampere) = a. 10.125 b. 0.48214285714286 c. 10.125 d. 3.375 i2 (in Ampere) = a. 5.6410714285714 b. 4.3392857142857 c. 1.125 d. 2.475 i3 (in ampere) = RI i4 (in ampere) = R2< 1₂ R32 13 R4 is

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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For R1=9, R2=1, R3=1, R4=1 and 15-13.5 A in the shown circuit, use current divider to find the following:
15
i1 (in Ampere) =
a. 10.125
b. 0.48214285714286
c. 10.125
d. 3.375
i2 (in Ampere) =
a. 5.6410714285714
b. 4.3392857142857
c. 1.125
d. 2.475
i3 (in ampere) =
RI
i4 (in ampere) =
R2<
1₂
R32
13
R4
is
Transcribed Image Text:For R1=9, R2=1, R3=1, R4=1 and 15-13.5 A in the shown circuit, use current divider to find the following: 15 i1 (in Ampere) = a. 10.125 b. 0.48214285714286 c. 10.125 d. 3.375 i2 (in Ampere) = a. 5.6410714285714 b. 4.3392857142857 c. 1.125 d. 2.475 i3 (in ampere) = RI i4 (in ampere) = R2< 1₂ R32 13 R4 is
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