For the following figure, the mass of the box is 32 kg the stiffness of the spring is 500 N/m and the radius r=18 cm (Hint: Jo-10)The Kinetic energy will be in the form ofQ0²T =The Potential energy will be in the form ofU=P 0²After Applying the Energy method to calculate the equation of motion, the form of the equation of the motion will be as:A + BO=0OA mThe constant Qis: Choose..The constant A isThe constant B is:The constant P isChoose.Choose.Choose4rX(t)Ok

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For the following figure, the m The Kinetic energy will be in the form of T = Q8² The Potential energy will be in the form of U-P0² kg the stiffness of the After Applying the Energy method to calculate the equation of motion, the form the form of the equation of the motion will be as AB + Be=0

For the following figure, the m The Kinetic energy will be in the form of T = Q8² The Potential energy will be in the form of U-P0² kg the stiffness of the After Applying the Energy method to calculate the equation of motion, the form the form of the equation of the motion will be as AB + Be=0

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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