For the following one-line diagram, determine: a) The power S, P, Q and the pf of the balanced three-phase generator, b) The efficiencies of lines 1 and 2.. c) The flow diagram of: full three-phase power. Remember to include all the losses associated with each of the lines (input, output and losses) (

For the following one-line diagram, determine: a) The power S, P, Q and the pf of the balanced three-phase generator, b) The efficiencies of lines 1 and 2.. c) The flow diagram of: full three-phase power. Remember to include all the losses associated with each of the lines (input, output and losses) (

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Qa1. The three phases of a generator can be connected in either delia (D) or wye (Y) connection. List two advantages of three phase system over a single phase system. Also write mathematical relationship between the phase voltage and the ine voltage, and the phase current and the line current for both delia (D) and wye (Y) connections. Please answer in typing format please..
Q2) A 13.2-kV single-phase generator supplies power to a load through a transmission line. The load's impedance is Ztoad 500 236.87° ohm , and the transmission line's impedance is Zine = 60 253.1° ohm. To reduce transmission line losses to 0.0103 of its losses without using the transformers design and use two transformers T1 between the generator and the transmission line and T2 between the transmission line and the load.
The one-line diagram of a three-phase power system is shown in the above figure. The line impedances are in per- unit on a 100-MVA base, and the line admittances are neglected. Use Gauss-Seidel method in Matlab to analyze the system the tolerance of error is 10-3. Then anwser the questions as follows. V, = 1.05200 0.01+ j0.025 300 + j200 MVA 0.015 + j0.035 150 MW 200 +j150 MVA 0.01+ j0.03 |V = 1.03 The admittance matrix (Y_bus)? 0.02 + jo.04 0.0125 + jo.03 2.
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