For the long (into the screen) triangular enclosure shown below, find the view factor from surface 1 to surface 3 (i.e. F13 ) L, = Lz 45° L3 = 3ft 0.7071 O 0.75 0.5 0.668
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- 1.26 Repeat Problem 1.25 but assume that the surface of the storage vessel has an absorbance (equal to the emittance) of 0.1. Then determine the rate of evaporation of the liquid oxygen in kilograms per second and pounds per hour, assuming that convection can be neglected. The heat of vaporization of oxygen at –183°C is .1.25 A spherical vessel, 0.3 m in diameter, is located in a large room whose walls are at 27°C (see sketch). If the vessel is used to store liquid oxygen at –183°C and both the surface of the storage vessel and the walls of the room are black, calculate the rate of heat transfer by radiation to the liquid oxygen in watts and in Btu/h.Two circular plates of radii r1= 4 cm and r2 = 2 cm are (9) cm apart. Find view factorF21.
- please answer it correctly stepwise. will give you thumbsup. this is a complete question. you just have to find view factors or shape factors of this figureEarth absorbs solar energy and radiates infrared energy. The intensity of the solar radiation incident on earth is J = 1350 Wm-2, also known as the solar constant. Assume earth’s surface (ground) temperature to be uniform at Ts, and that the ground and atmosphere are black (emissivity = 1) for infrared radiation. The radius of the earth is 6.378 x 106 m. The diagram shows the ground at the surface temperature Ts and the atmosphere, represented as a thin black layer, at temperature Ta . Suppose the atmosphere absorbs 100% of the infrared radiation emitted by the ground. Assume that the ground absorbs 47.5% of the incident solar energy, and that the atmosphere absorbs 17.5% of the incident solar energy (for a total of 65% absorbed by the planet). Calculate the "steady state” numerical values of the earth’s ground temperature Ts and the atmospheric temperature Ta taking into account the “greenhouse effect” of atmospheric infrared absorption and emission described above.A right circular cylinder has a height of 1 m and diameter of 75 cm. Find the view factor for the cylindrical to the base.
- 2. Find the view factors for this configuration. a. Fis b. F13 2 c. F12 0.25 m -0.1m. 0.25 mImagine you have two concentric, coaxial cylindrical tubes with an evacuated annular space, with equal lengths L. The outer radius of the inner cylinder is r, and the inner radius of the outer cylinder is R. If we want to minimize the self-viewing factor of the inner surface of the outer cylinder, which of the following geometric changes would you suggest? r is fixed, decrease R with fixed R and L, decrease r with fixed r and R, decrease L R is fixed, increase L r is fixed, increase R3.Determine the total number of view factors that need to be evaluated directly for a 4-surface enclosure. 安苏白” 050E106 750E106
- Two square plates of equal side (5) cm are 15 cm apart. Find view factor F12. Two circular plates of radii r1= 4 cm and r2 = 2 cm are (4+N) cm apart. Find view factorF21. uses charts/table also if neededComplete the matrix of view factors below for the 4-Zone Enclosure: A1=1.25 in2; A2=2.75 in2; A3=3.67 in2; A4=5.72 in2 F23=0.7F22 a. What can you say about objects 1 and 3? b. What object transmits the largest portion of radiation interceted by object 3?Consider the right-circular cylinder of diameter D, length L, and the areas A1, A2, and A3 representing the base, inner, and top surfaces, respectively. (a) Show that the view factor between the base of the cylinder and the inner surface has the form, where H = L/D. F_{12}=2H\left[\left(1+H^2\right)^{\frac{1}{2}}-H\right]F12=2H[(1+H2)21−H] (b) Show that the view factor for the inner surface to itself has the form. F_{22}=1+H-\left(1+H^2\right)^{\frac{1}{2}}F22=1+H−(1+H2)21 8