For the purposes of fast modular exponentiation, compute 3183 mod 17 by instead computing the product of: 1483 (mod 17) 31643116312*31¹ (mod 17) 1415 mod 17 31403140313 (mod 17)
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- Use Modular Exponentiation method to find 5234mod 9.In the expansion of (4x -2/x)8 or (4x -2x^-1)8, find the following: a)the term containing x^6 b)the constant term (the term that does not contain x) I know a) is -262144x^6 and -4096/x^6 and b) is 286720 but i don't know how to do the formula of Tk+1 = C (n,k) a ^n-k x khow did they get 9x^2 from (x^4)/(5x^2)mod11 ?
- Expanding each integer in the expansion 21×12 gives the integer expansion [(2•10^1)+(1•10^0)•[(1•10^1)+(2•10^2)]. a. Replace the 10s with x’s to get a polynomial expression. b. Multiply the expressions using the foil method. Show all of the steps c. compare this process with the process used in Part 5. How are they familiar?Compute the binary form of 25 and 35, using division method and compute their sum in the binary notation.Check the results against adding 25 and 35 in the usual decimal notation and then converting it to binary.Use Fermat’s little theorem to find 23^1002 mod 41. Show each step ofyour computation.