For the reaction 2H₂S(g) = 2H₂(g) + S₂(g), K₂8.9x10² at 725 K. What will happen when 0.20 mol of H₂S, 2.5 mol of H₂, and 3.0 mol of S₂ are added to a 1.0-L container and the system is brought to 725 K? More H₂ will be formed than S₂. More H₂S will be formed. Nothing: the system is at equilibrium. The amount of H2₂ formed will be half the amount of S₂ formed.

Chemistry
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Chapter13: Chemical Equilibrium
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Problem 129MP: A gaseous material XY(g) dissociates to some extent to produce X(g) and Y(g): XY(g)X(g)+Y(g) A...
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For the reaction 2H₂S(g)
2H₂(g) + S₂(g), Ke-8.9x102 at 725 K.
What will happen when 0.20 mol of H₂S, 2.5 mol of H₂, and 3.0 mol of S₂ are added
to a 1.0-L container and the system is brought to 725 K?
More H₂ will be formed than S₂.
More H₂S will be formed.
Nothing; the system is at equilibrium.
The amount of H₂ formed will be half the amount of S₂ formed.
More S₂ will be formed than H₂.
Transcribed Image Text:For the reaction 2H₂S(g) 2H₂(g) + S₂(g), Ke-8.9x102 at 725 K. What will happen when 0.20 mol of H₂S, 2.5 mol of H₂, and 3.0 mol of S₂ are added to a 1.0-L container and the system is brought to 725 K? More H₂ will be formed than S₂. More H₂S will be formed. Nothing; the system is at equilibrium. The amount of H₂ formed will be half the amount of S₂ formed. More S₂ will be formed than H₂.
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