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- An organic chemistry experiment involves a nucleophilic substitution (SN2) reaction using 1-iodobutane and 2-naphthoxide ion. The 2-naphthoxide ion is generated from 2-naphthol and sodium hydroxide in an ethanol solvent. The experiment includes steps like generating the nucleophile, conducting the SN2 reaction, and analyzing the product using 1H NMR spectroscopy. Question: Write the structure of the undesired side product if CH3CH2O‾ (ethoxide) reacts with 1-iodobutane.(11) Draw the major organic product of the reaction. Follow this procedure: determine whether the reaction conditions are acidic or basic; identify the most nucleophilic/basic atom, the electrophilic atom, and the leaving group; predict whether elimination or substitution will occur; and then draw the product. Indicate the stereochemistry at every stereocenter with a single wedged (up), hashed (down), or wavy (a mixture of up and down; either) bond. Launch Marvin JS TM viewer or click image to copy source HN CI Ο N-KAcyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. CI + H₂N • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. OH • Do not include counter-ions, e.g., Na+, I¯, in your answer. • In cases where there is more than one answer, just draw one.
- Acyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. H3C NH₂ HCI/H₂O reflux • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. • Do not include counter-ions, e.g., Na+, I, in your answer. • In cases where there is more than one answer, just draw one.a) Free radical bromination is more selective than free radical chlorination. Draw a reaction coordinate diagram for the specific step in the radical chain mechanism that illustrates the source of this selectivity, and explain your reasoning. b) Explain why the bond dissociate energy (BDE) of tert-butane is 95 kcal/mol while the BDE for propane is 99 kcal/mol.Complete the generic mechanism for an electrophilic aromatic substitution (EAS) reaction using E as the electrophile, and show how the sigma complex is resonance stabilized. Use curved arrows to show the mechanism and the conversion between resonance structures. Make sure to add any missing charges. Note the use of a generic base (B) in the last step. Then, label the reaction coordinate diagram for a typical EAS reaction by correctly placing the structures on the diagram. Step 1: add a curved arrow. Select / |||||| Draw CH Rings Groups More Erase slow WE
- please do the mechanism. Identify which one is the nucleophile/electrophile. Name the reaction as well. Discuss the stereochemistry so why the dash bond go to wedged- due to inversion? Why is PPh3 used for selectivity ? Please answer all of my questions.Alcohols are acidic in nature. Therefore, a strong base can abstract the acidic hydrogen atom of the alcohol in a process known as deprotonation. The alcohol forms an alkoxide ion by losing the proton attached to the oxygen atom of the hydroxyl ( -OH) group. The alkoxide formed can act as a base or a nucleophile depending on the substrate and reaction conditions. However, not all bases can abstract the acidic proton of alcohols and not all alcohols easily lose the proton. Deprotonation depends on the strength of the base and the acidity of the alcohol. Strong bases, such as NaNH2, can easily abstract a proton from almost all alcohols. Likewise, more acidic alcohols lose a proton more easily. Determine which of the following reactions would undergo deprotonation based on the strength of the base and the acidity of the alcohol. Check all that apply. ► View Available Hint(s) CH3CH,OH + NH3 →CH,CH,O-NH CH3 CH3 H3C-C-H+NH3 → H3 C-C-H OH O-NH CH3CH2OH + NaNH, → CH3CH,O-Na* + NH3 CHC12 Cl₂…What is true regarding the reaction of acetyl chloride and methylamine ? Multi-select. Select all that apply. ) This reaction follows the mechanism of nucleophilic acyl substitution. Methyl amine acts as a base in this reaction. O Acetyl chloride acts as electrophile in this reaction. O Chloride acts as a nucleophile in this reaction. This reaction is faster than reaction of benzoyl chloride with ethylamine.
- When HCI, HBr, and HI were used as HX in the next reaction, the rates of all reactions were almost the same. below Answer the question. OH HX CH3 CH3 H2O (1) Show the ions that act as each nucleophile in order from the one that is considered to have the highest nucleophilic reactivity. (2) Explain the reason why you thought that the order was (1). (3) Explain why the reaction rates were almost the same regardless of which HX was used. (4) Nax was used instead of HX, but the reaction did not proceed. Explain the reason for this.For the given Sy2 reaction, draw the organic and inorganic products of the reaction, and identify the nucleophile, substrate, and leaving group. Include wedge-and-dash bonds and draw hydrogen on a stereocenter. :CEN Organic product Inorganic product + Draw the organic product. Draw the inorganic product. IncorrectIV. TEACHING AND LEARNING ACTIVITIES Name Date Score Year & Section 1. Question : Arrange the following compounds in increasing order of their boiling points, CH3CHO, CH3CH₂OH, CH3OCH3, CH3CH₂CH3 2. Question : Arrange the following compounds in increasing order of their reactivity in nucleophilic addition reactions (i) Ethanal, Propanal, Propanone, Butanone. (ii) Benzaldehyde, p-tolualdehyde, p-nitrobenzaldehyde, acetophenone.