Solve all parts Will definitely upvote Letf(x) = ln(2x+1), x = (1,3).1. The Taylor polynomial T2 (x) at the pointa = 2 is2. The smallest value of M that occurs inTaylor's inequality is3. With M having the above value, Taylor'sinequality assures that the error in theapproximation f(x) ≈ T2(x) is less thanx = (1,3).for all4. If x (2, 3) the Alternate SeriesEstimation Theorem assures that the error inthe approximation f(x) ≈ T₂ (x) is lessthanNotice: Your input in 3. and 4. should containthe smallest possible value, as indicated byTaylor Inequality and ASET.

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Answered: f(x) = ln(2⋅ x + 1), x € (1, 3). 1. The…

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f(x) = ln(2⋅ x + 1), x € (1, 3). 1. The Taylor polynomial T2 (x) at the point a = 2 is

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter7: Analytic Trigonometry

Section7.6: The Inverse Trigonometric Functions

Problem 91E

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Solve all parts Will definitely upvote

Let
f(x) = ln(2x+1), x = (1,3).
1. The Taylor polynomial T2 (x) at the point
a = 2 is
2. The smallest value of M that occurs in
Taylor's inequality is
3. With M having the above value, Taylor's
inequality assures that the error in the
approximation f(x) ≈ T2(x) is less than
x = (1,3).
for all
4. If x (2, 3) the Alternate Series
Estimation Theorem assures that the error in
the approximation f(x) ≈ T₂ (x) is less
than
Notice: Your input in 3. and 4. should contain
the smallest possible value, as indicated by
Taylor Inequality and ASET.

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