Coding assistance. fs= .00743 G" =Plot both G1 vsB flfs +.1+ B. G*√B0.571+√√f/2(g Prº. B)(1+B) 1.07 +12.7√√/2 (P-1)and G2 vs√√₁on the same graph. The solution is where the1√ √=8two lines intersect. The solution should occur at G* = 1.23 and(1)= 8.823. With √√2/f known, calculate St from equation 9.25 of the book using n = 0.57.4.Solve for A/A, from Eq. 5b (from the appendix of the Chapter 8 problem)evaluated at Q/Qs = 1. Note that ß= B. for the rib roughness because the heattransfer coefficient is based on the smooth tube area, i.e., A/L = As/L.5. The associated e/D is calculated from e+ = (e/D)Re√√f/26. The remaining parameters (N/Ns, L/Ls) are easily calculated. Calculate thematerial savings for the VG-1 case offered by two-dimensional rib roughness. For thisroughness, the geometrical parameters are e/D, ple, tle, a. Calculate the materialsavings for a = 90° with p/e = 10, t/e = 0.5, while using the smooth tube operatingparameters as used in the Chapter 8 problem: Res = 12320, Pr = 62, oil, etc.Because fand St are functions of e/D and et (or Re), the PEC equation for A/Asimplicitly contains two independent variables: e/D and et. Therefore, a range ofsolutions exist. Corresponding to each arbitrary value of et is a particular value of Re(or Gs/G) required to satisfy the constraints (P/Ps = Q/Qs = 1). And, with et and Redefined, e/D is known and calculated from eq. (9.9) of the book: (e/D=et/ (Re√√f/2)). Therefore, one should calculate A/As for a range of e* (or Re) todefine the minimum A/As. Webb and Eckert (1972) have calculated A/As vs. Gs/G forple = 10, a = 90° roughness over a range of Re (or Gs/G) and Pr and suggest that e* =20 is a reasonably good design specification for the VG-1 criterion. However, if theA/As vs. Gs/G curve shows a fairly flat minimum, the required flow frontal area willincrease with increasing e* (or e/D).For this problem, we will select et = 20 for our design specification, which fixes theg (et) and B(e) contained in the correlations for fand St. These values are: a = 90°:at e = 20, B = 4.2, g = 11.Use the following iterative solution outlined below and given in the notes:1. Assume G* = G/G. So Re = Res/ G*2. Solve for G* from eq. (22) of Webb and Eckert (1972):G=Re2e+V.₁expDevise a computer code to generate an array forin increments of 0.01. Use the√F-√21f- -3.752.5array Gl. Use the G1 array and the√with values from 7 to 11array to evaluate eq. (22) for G*. This willgive you an array of G* for values associated with theF1₁array. Call this G*array to evaluate a new G usingeq. (1) of your roughness class notes given below (i.e., eq. (17) of Webb andEckert, 1972) with r = Bs, (call this array G2):¹Please use the Filonenko and Petuknov equations to calculate fs and Sts, respectively, for this problem.

It is asked to find the intersecting value from the plot

G= Plot both G1 vs = B, flfs + 1+√√f/2(g Pr0.57-B) 2/3 1+B, G (1+B)1.07+12.7 √,/2 (Pr2³-1)] E and G2 vs F on the same graph. The solution is where the two lines intersect. The solution should occur at G = 1.23 and 長 √F (1) 8.82 3. With √ √2/f known, calculate St from equation 9.25 of the book using n = 0.57. 4. Solve for A/A, from Eq. 5b (from the appendix of the Chapter 8 problem) evaluated at Q/Qs = 1. Note that ß= ß, for the rib roughness because the heat transfer coefficient is based on the smooth tube area, i.e., A/L = A/L. 5. The associated e/D is calculated from e* = (e/D)Re√√f/2 6. The remaining parameters (N/Ns, L/Ls) are easily calculated.

G= Plot both G1 vs = B, flfs + 1+√√f/2(g Pr0.57-B) 2/3 1+B, G (1+B)1.07+12.7 √,/2 (Pr2³-1)] E and G2 vs F on the same graph. The solution is where the two lines intersect. The solution should occur at G = 1.23 and 長 √F (1) 8.82 3. With √ √2/f known, calculate St from equation 9.25 of the book using n = 0.57. 4. Solve for A/A, from Eq. 5b (from the appendix of the Chapter 8 problem) evaluated at Q/Qs = 1. Note that ß= ß, for the rib roughness because the heat transfer coefficient is based on the smooth tube area, i.e., A/L = A/L. 5. The associated e/D is calculated from e* = (e/D)Re√√f/2 6. The remaining parameters (N/Ns, L/Ls) are easily calculated.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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