Geosynchronous orbit is a stationary orbit with period of rotation equal to the sideral period of rotation of the Earth 23h56 min. Find the radius of a geosynchronous orbit. Find the radius of a stationary orbit around Jupiter.
Geosynchronous orbit is a stationary orbit with period of rotation equal to the sideral period of rotation of the Earth 23h56 min. Find the radius of a geosynchronous orbit. Find the radius of a stationary orbit around Jupiter.
Applications and Investigations in Earth Science (9th Edition)
9th Edition
ISBN:9780134746241
Author:Edward J. Tarbuck, Frederick K. Lutgens, Dennis G. Tasa
Publisher:Edward J. Tarbuck, Frederick K. Lutgens, Dennis G. Tasa
Chapter1: The Study Of Minerals
Section: Chapter Questions
Problem 1LR
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The expert did not answer correctly because when you do the calculations, the final answer is different. Can you solve it again
![00:46
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✓ ANSWERED
Sunday, Oct 01, 2023
SCIENCE PHYSICS
Geosynchronous orbit is a stationary orbit with
period of rotation equal to the sideral period of
rotation of the Earth 23h56 min. Find the radius of a
geosynchronous orbit. Find the radius of a stationary
orbit around Jupiter.
Expert Answer
Step1
a)
in order to
is
where
rotation.
GMon=
p.².
GM
m
stay.
radius is
r =
in orbit the
Pa
mw²
(27) r
----
GMT
47²
M = mass of planet T = Time preciod of
n = readius.
3]
.5G
@ in case of stationaly orbit around earth is
To 23 hr 56 min.
GMT
4712
fonce equation
= 42220000 m
667x10x 6×1024 x (23x 3600 +56 x 60)²
4712
√x
Do
8](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe64261ed-a22c-44ce-964e-050681d05be9%2F96e03b5a-397b-4af5-902e-3272573cd7fb%2Fqfedg6d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:00:46
←
✓ ANSWERED
Sunday, Oct 01, 2023
SCIENCE PHYSICS
Geosynchronous orbit is a stationary orbit with
period of rotation equal to the sideral period of
rotation of the Earth 23h56 min. Find the radius of a
geosynchronous orbit. Find the radius of a stationary
orbit around Jupiter.
Expert Answer
Step1
a)
in order to
is
where
rotation.
GMon=
p.².
GM
m
stay.
radius is
r =
in orbit the
Pa
mw²
(27) r
----
GMT
47²
M = mass of planet T = Time preciod of
n = readius.
3]
.5G
@ in case of stationaly orbit around earth is
To 23 hr 56 min.
GMT
4712
fonce equation
= 42220000 m
667x10x 6×1024 x (23x 3600 +56 x 60)²
4712
√x
Do
8
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