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Given = 3.0 M Ca(oH)2 & 2.5L Looking For = g CacOH)z mol = M x L = (3.0MX25 L) mol= 7,5 mol Cal0H )2 M= mol Calx40.08 = 40.08 1 x16.00 = 116 -DO | x 1.01 1. 57.09 g/mol CacoH)2 7.5 mol Ca(oH)z 57.09g Ca(ott)z= 428.18g I mol Ca(oH) 2 CaOH Y2 The student got the answer wrong. Identify the error, explain the mistake in detail and fix it by providing the correct answer.

Given = 3.0 M Ca(oH)2 & 2.5L Looking For = g CacOH)z mol = M x L = (3.0MX25 L) mol= 7,5 mol Cal0H )2 M= mol Calx40.08 = 40.08 1 x16.00 = 116 -DO | x 1.01 1. 57.09 g/mol CacoH)2 7.5 mol Ca(oH)z 57.09g Ca(ott)z= 428.18g I mol Ca(oH) 2 CaOH Y2 The student got the answer wrong. Identify the error, explain the mistake in detail and fix it by providing the correct answer.

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter4: Stoichiometry: Quantitative Information About Chemical Reactions
Section: Chapter Questions
Problem 76PS: Vitamin C has the formula C6H8O6. Besides being an acid, it is a reducing agent. One method for...
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Given = 3.0 M Ca(oH)2 & 2.5L Looking For = g CacoH)2 M × L = (3.0m)25L) mol= 7.5 mol CaoH )z M= mol mol = Calx40.08 = 40.08 0 I x16.0 0 = ll6-0 0 I x 1.0 1 1.0 57.09 g/mol CacoH)2 7.5 mol CaloH)z 57.09gCa(ott)[428.189 I mol CaloH) z CaOH2 The student got the answer wrong. Identify the error, explain the mistake in detail and fix it by providing the correct answer.
Transcribed Image Text:Given = 3.0 M Ca(oH)2 & 2.5L Looking For = g CacoH)2 M × L = (3.0m)25L) mol= 7.5 mol CaoH )z M= mol mol = Calx40.08 = 40.08 0 I x16.0 0 = ll6-0 0 I x 1.0 1 1.0 57.09 g/mol CacoH)2 7.5 mol CaloH)z 57.09gCa(ott)[428.189 I mol CaloH) z CaOH2 The student got the answer wrong. Identify the error, explain the mistake in detail and fix it by providing the correct answer.
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