Given a common-base amplifier circuit: VCC = 15 V, R1 = 50 kN, R2 = 10 kN, RC = 2 kN, RE = 1 kN, RL = 1 kQ, Is = 50 fA, ß = 120 A/A, VT = 25 mV, Vin = 10 mV. R1 RC VC Cc2 out *RL Q1 Cc1 in Vin Cb1 R2 RE
Given a common-base amplifier circuit: VCC = 15 V, R1 = 50 kN, R2 = 10 kN, RC = 2 kN, RE = 1 kN, RL = 1 kQ, Is = 50 fA, ß = 120 A/A, VT = 25 mV, Vin = 10 mV. R1 RC VC Cc2 out *RL Q1 Cc1 in Vin Cb1 R2 RE
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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for this particular circuit, what formula should I use for Rin(emitter)?
![Given a common-base amplifier circuit:
VCC = 15 V, R1 = 50 kQ, R2 = 10 kN, RC = 2 kN, RE = 1 k,
RL = 1 kQ, Is = 50 fA, B = 120 A/A, VT = 25 mV, Vin = 10 mV.
%3D
R1
RC
VC
Cc2
out
*RL
Q1
Сс1
in
Vin
Cb1
R2
RE](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F05a60b4b-e282-417a-93f9-b449eb57a874%2Fce64b4e0-7072-460e-afee-1cc034eca88d%2Fhuk0rte_processed.png&w=3840&q=75)
Transcribed Image Text:Given a common-base amplifier circuit:
VCC = 15 V, R1 = 50 kQ, R2 = 10 kN, RC = 2 kN, RE = 1 k,
RL = 1 kQ, Is = 50 fA, B = 120 A/A, VT = 25 mV, Vin = 10 mV.
%3D
R1
RC
VC
Cc2
out
*RL
Q1
Сс1
in
Vin
Cb1
R2
RE
![Input resistance at emitter:
Ain(eminer) =e
or
ve
Rinie)
%3D
-ie
-ie
-ie
B +1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F05a60b4b-e282-417a-93f9-b449eb57a874%2Fce64b4e0-7072-460e-afee-1cc034eca88d%2F04qwr7_processed.png&w=3840&q=75)
Transcribed Image Text:Input resistance at emitter:
Ain(eminer) =e
or
ve
Rinie)
%3D
-ie
-ie
-ie
B +1
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