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- 80mL of a 0.3M solution of hexapeptide Leu-His-Cys-Glu-Asn-Arg is adjusted to pH=pI. The solution is then titrated with 0.2M HCL to a final pH of 2.1. Sketch the titration curve, labelling the pH and volume axes. Indicate the volume of HCL needed to reach relevant pKa value and equivalence point(s)z Relevant pKa values are: 2.1, 4.3, 6.0, 8.3, 9.8, and 12.5.A monoprotic weak acid, HA, dissociates in water according to the reaction HA(aq) = H*(aq) + A¯(aq) The equilibrium concentrations of the reactants and products are [HA] = 0.290 M, H+| = 3.00 × 10¬4 M, and [A-] = 3.00 x 10-4 M. Calculate the value of pKa for the acid HA. pKaHighlight your values of A,B,C and D. For your question: A mL of B mol/L sodium phosphate solution is combined with C mL of D mol/L calcium bicarbonate. (Calcium bicarbonate is soluble.) A mL B mol/L C mL D mol/L 75.0 ml 0.300 67.5 0.350 Before you begin your reaction, you must accurately produce 1.500 L of your sodium phosphate solution from sodium phosphate trihydrate solid. Write out a procedure to explain all the steps you will take in the lab when making the solution to ensure that your solution concentration is accurate. Please include calculations that show the required mass of solid. Also include the correct names of all equipment used.
- Quinine ( C20 H24 N2 O2) is the most important alkaloid derived from cinchona bark. It is used as an antimalarial drug. For quinine, pK, = 5.1 and pK, = 9.7 ( pKp = – log Kp). Only 1 g quinine will dissolve in 1920.0 mL of solution. Calculate the pH of a saturated aqueous solution of quinine. Consider only the reaction | Q+ H2O= QH+ + OH- described by pK, where Q = quinine. pH =at 257 nm) is dissolved in 2.5 mL of buffer. A 250 microliter aliquot is removed and placed in a 1.0 cm A sample of adenosine triphosphate (ATP) (MW 507, ɛ = 14,700 M'cm cuvette with sufficient buffer to give a total volume of 2.0 mL. The absorbance of the sample at 257 nm is 2.0. Calculate the weight of ATP in the original 2.5 mL sample. (Choose the correct value from the drop-down list provided. The values of weight are listed in units of milligrams.) Weight of ATP: v mgWhat volume of 0.1M NaOH (reagent) needs to be added to increase your 7.5 pH (buffer) by 0.5 pH units. The goal is to further purify MOPs (see image). Protonated form = 6.6 x 10.3^-3 mol/L Deprotonated form = 1.32 x 10^-2 mol/L Show calculations.
- The isoelectric point of eIF4a is 5.02. Students are given a sample of cell lysate containing eIF4A at pH 7.4. They are also provided with two buffers of pH 7.4 to use for ion exchange chromatography. One buffer has a very high salt concentration (1 M), the other has a low salt concentration (0.1 M). Mariela decides to use an anion exchange column, while Ashok chooses a cation exchange column. Who made the better decision? Provide a detailed explanation of why one student will end up with a purer sample of eIF4A. Which buffer will you use while washing away impurities (high or low salt), and which would you use to remove eIF4A from the column? Explain your choice.Consider a buffer solution of acetate. The volume is 500 ml, the concentration is 200 mM, and the pH is 5.0. a. How many total moles of acetate plus acetic acid are present in the solution? Express answer as x.y with one digit before and one after the decimal place. b. What is the ratio of acetate ions (Ac-) to acetic acid ions (HAc) in the buffer solution (pH 5.0) if the pka is 4.76? Express the answer as x.yz with one digit before and two after the decimal place. c. How many moles of acetate are present in the solution? Express your answer to one decimal place. d. How many moles of acetic acid are present in the solution? Express your answer to one decimal place.The reaction quotient is Q=1.6×10-26 Part B What pH is needed to produce this value of Q if the concentration and pressure values are [Br2]=2.50×10−4M , [Br−]=11.65M, [SO42−]=9.50M, and PSO2=3.50×10−5atm ? Express your answer numerically to two decimal places.
- A patient presents to the emergency department in a critical condition. The patient’s blood was tested and the concentration of carbonic acid (H2CO3) was found to be 4.0×10-4 M and bicarbonate ion (HCO3-) 3.062×10-3 M. Ka = 4.3 × 10-7 H2CO3(aq) ⇌ HCO3-(aq) + H+(aq) Show all calculations including equation(s) used. Calculate the pH of the patients’ blood. Based on your answer would you say the patient is suffering from Acidosis or Alkalosis?Calculate the concentration of Y4-ion in 0.0100 M EDTA solution at pH 6. α4 = 2.2 x 10-5 for pH 6.A 10.00-mL aliquot of unknown oxalic acid solution required 15.44 mL of 0.011 17 M KMnO4 solution to reach the purple end point. A blank titration of 10 mL of similar solution containing no oxalic acid required 0.04 mL to exhibit detectable color. Find the concentration of oxalic acid in the unknown.