Given: PD = 250kips and PL = 350 kips. The member is 30 ft long with pinned end, supports and is laterally supported in the weak direction at the one-third points of the total column length. Find: : The lightest W12 section to support the loads. Use design tables in part 4 of AISC Manual. LRFD and ASD
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Given: PD = 250kips and PL = 350 kips. The member is 30 ft long with pinned end, supports and is laterally supported in the weak direction at the one-third points of the total column length.
Find: : The lightest W12 section to support the loads. Use design tables in part 4 of AISC Manual. LRFD and ASD. Step by step method of solving please
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- 0O REDMI NOTE 8 PRO O AI QUAD CAMERA Q - 4. For the given truss structure below; BY USING THE METHOD of SECTIONS; determine the internal forces of the elements BD, CD & CE. Also determine whether these forces are TENSILE or COMPRESSIVE. 3 in 3 m -4 m -4 m -4 m- 1.75 kN 2KN 1.5 kN 2kN I kN 9.75 kN G 6 m 6 m 6m 6 mThe truss shown is composed of steel sections. If the 2L150 x 90 x 8 A36 steel section was used in member CG, is it satisfactory? Use 2 lines of 4-20mm fasteners spaced 75 mm on center for all joints. The loads applied in the truss are. service loads. Use ASD only. You can use ASEP Manual. Multiply the loads by 10. 50 kN 30 kN- 3 m G 3 m 3 m 30 kN- D 30 kN- A m E H m C1. A one-bay one-story frame, shown in the Fig. 1, consist of a truss system. Two different types of connections are proposed for the 1s joint. Check the all requirements for tension. All dimensions are given in cm. M20 bolts with standard holes are used. S355 Structural Steel is used in all parts (F 355 MPa and F-490 MPa). 2 3 Lateral Load Please explain the solution, step by step! For example sketch the net areas show how to calculated! 4 5 An IPE beam is used to carry axial tension load (P) for the 4th member. a. Calculate the tensile strength (P) of the member according to AISC 360 LRFD and ASD. b. Determine the thickness (t) of the gusset plate according to max. tensile load calculated in part (a). 4,05 4,05 IPE360 P 26 Cross-sectional View Side View Top View
- 1. Check the following members for Tension, Compression, and Flexure utilizing AISC and H-Code. All loads are factored, and all steel is A36. a. Angle: L3x3x1/4 b. HSS: H4x4x1/4 C. Pipe: P2 STD 1.6 Kips 2Kips 6-0"PSD323- Principles of Steel Design 4. The tee section is made up of a 30mmx150mm flange and a 30mmx160mm web. Determine the properties of a section(MOI, section modulus, radius of gyration) 15d mm 30 mm A, 6 Yu d, N.A. di 30 tnm 160 mmA W18 3 119 is used as a compression member with one end fixed and the other end pinned. The length is 12 feet. What is the available compressive strength if A992 steel is used? a. Use AISC Equation E3-2 or E3-3. Compute both the design strength for LRFD and the allowable strength for ASD. b. Use Table 4-14 from Part 4 of the Manual. Compute both the design strength for LRFD and the allowable strength for ASD.
- Bottom chord of truss is composed of two angle bars each having a dimension of 185 mm x 146 mm x 8.7 mm. Between them is a gusset plate, 9.5mm thick. At each end of joints, four 19mm-dia. bolts are fastened along the gage line, having an edge distance of 44 mm and 59mm pitch. Use A36 steel Fy 248 MPa Fu = 400 MPa %3D spacing of bolt = 68.9 mm %3D 9 5mm thick gunset plate edge dist Compute the capacity of the bottom chord based on block shear strength, in KN. uadThe section shown carries a total service tension load of 15708 kN with a dead to live load ratio of 2:3. If the tension member has a length of 3 meters and A36 steel, determine the following: a. The effective net area b. The LRFD design strength c. The ASD design strength d. Is the section adequate? Note that the bolt diameter is 28 mm. section: W40x244 g1=150 g2=100 s1=125 s2=100 s3=15004. For the truss shown below, design member HI using W shape of A992 steel. The loads acting on the truss are the design panel loads. Assume that each flange will be connected to a 20-mm thick gusset plate with two lines of three-20-mm diameter bolts as shown in the detail. For this connection, assume that U = 0.85. The size of the member should be controlled so you must limit your selections to W8, W10, and W12 sections. 80 KN B 80 kN 80 KN 80⁰ kN 80 kN =I=I1=IS DETAIL OF CONNECTION D H 80 kN 5 @ 5m= 25 m a.com 80 kN E F 40 kN GIVEN: STEEL GRADE: A992 Steel t = 20mm Length = 5m h = 5m 40 kN REQUIRED: Design of Member HI using W shape + Test Adequacy 5 m
- A W300x67 has two lines of 20mm dia. bolts in each flange (three bolts in each line which has a spacing as shown in the figure. A36 steel is used with Fy = 250MPA, Fu = 400MPA. a. Compute the effective net area of the section. b. Compute the allowable tensile strength of the section. c. Compute the ultimate tensile strength of the section. d. Compute the block shear strength of the section. 201.05 23 50 75 75 14.4 Properties of W300x67 A = 8,250mm2 b; = 201.05mm t= 14.40mm d = 300mm tw = 8.4mm 300 201.05 O O O 32 14.4 23 235.3 02) The member (W30 292) shown in Figure below is braced against sidesway. Bending is about the major axis. Does this member satisfy the provisions of the AISC Specification? The loads are 40% live load and 60% dead load. (625 k 195 ft-k A992 225 ft-k4. The steel truss that is shown in the Figure below is loaded with three concentrated service live loads applied at B, D, and F. Assume lateral support is provided only at joints. Assume that the effective area is 85% of the computed net area. Use 20 mm ø bolts, Fy = 250 MPa, and Fu = 400 MPa. a. Investigate the adequacy of L51X51X7.9 at member IJ. b. Investigate the adequacy of L64X64X7.9 at member DI. 125 125 P= KN 125 P= KN P= KN 6@2m =12m %3D