Given the following CFG S → OB A → IAA|A B → OAA The following strings can be generated except i. 001 ii. 000 iii.0011 iv. 01 O A. i and iii O B. i and ii O C. iv only O D. ii only
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- A string may use more than one type of delimiter to bracket information into blocks. For example, a string may use braces { }, parentheses ( ), and brackets [ ] as delimiters. A string is properly delimited if each right delimiter is matched with a preceding left delimiter of the same type in such a way that either the resulting blocks of information are disjoint, or one of them is completely nested within the other. Write a program that uses a single stack to check whether a string containing braces, parentheses, and brackets is properly delimited.Use input file string.txt as input to test your program.Each line in the input file is a string. If the string is properly delimited, display a message stating so. If it is not properly delimited, display a message stating so.For example, if the input file contains the following 3 lines of strings:if (a[i] > b[i])while (c[index] < 0) { a++; b--; c[index++];}for ({int i = 0; num[i }];would display the following output: Processing…S is a set of strings recursively defined as follows. Base case: Every variable from the set {a, b, c, d, e, f} is in S. Recursive rules: If x = S and y = S, then: 1. (x + y) Є S 2. x.yЄ S Indicate which expressions are in S. ☐ (d.e.a) a+b a.b.c ☐ (a + d).eA string may use more than one type of delimiter to bracket information into “blocks.” For example, A string may use braces { }, parentheses ( ), and brackets [ ] as delimiters. A string is properly delimited if each right delimiter is matched with a preceding left delimiter of the same type in such a way that the either the resulting blocks of information are disjoint, or one of them is completely nested within the other. Write a program that uses a single stack to check whether a string containing braces, parentheses, and brackets is properly delimited.
- utogwVUfWNJvmW7MGwYrTyRrJDu-ioEw19ELum82_RuHi-A/formResponse?pli=1 Consider a grade-averaging scheme in which the final average of a student's scores is computed differently from the traditional average if the student has completed a make-up assignment: drop the lowest score and compute the new average. The following table shows several example scores and how they would be average using the scheme described above. Student Scores Make-Up Completed? Final Average 50, 50, 20, 80, 53 No (50 + 50 + 20 + 80 + 53)/5.0 = 50.6 30, 80, 85, 87 Yes (80 + 85+ 87)/3.0 = 84.0 75, 85, 10, 60, 90 Yes (75 + 85+ 60 + 90)/4.0 = 77.5 Consider the following incomplete StudentRecord class. Each studentRecord object stores a list of that student's scores and contains methods to compute that student's final average. public class StudentRecord private int [] scores; // contains scores.length values // scores.length > 1 // constructors and other data fields not shown // returns the average (arithmetic mean)…CodeW For fun X C Solved https://codeworkou... 臺亂 CodeWorkout X272: Recursion Programming Exercise: Is Reverse For function isReverse, write the two missing base case conditions. Given two strings, this function returns true if the two strings are identical, but are in reverse order. Otherwise it returns false. For example, if the inputs are "tac" and "cat", then the function should return true. Examples: isReverse("tac", "cat") -> true Your Answer: 1 public boolean isReverse(String s1, String s2) { 2. if > 3. 4. else if > return true; return false; 5. 6. else { String s1first = String s2last return s1first.equals (s2last) && 51. substring(0, 1); s2, substring(s2.length() 1); 7. 8. 6. isReverse(s1.substring(1), s2.substring(0, s2.length() 1)); { 12} 1:11AM 50°F Clear 12/4/2021Assignment Content Given two strings s and t, determine if they are isomorphic. Two strings s and t are isomorphic if the characters in s can be replaced to get t. All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character, but a character may map to itself. Example 1: Input: s="egg", t = "add" Output: true Example 2: Input: s="foo", t = "bar" Output: false Example 3: Input: s= "paper", t = "title" Output: true
- Q5: Design a PDA for accepting a language (0"1"0 | m, n-1} give the ID form as we explain in the lecture. Apply the string "00011000" on this PDA using ID transitions.Write in C Language Spilitology Yosef is a peculiar fellow. He introduced the idea to study a string by splitting it into two, and he called it Splitology. Why split a string? We do not know. Didn’t we say that Yosef is a weird one? Yosef is interested in one particular type of string, a palindrome. A palindrome is a string that is the same for both forwards and backwards. Example of palindrome strings are “ada”, “taat”, and “radar”. On the other hand, string such as “taman” is not a palindrome; notice that “taman” becomes “namat” if read backwardsand it’s not the same as “taman”. As the idea of Splitology is still new, Yosef is investigating whether a string can be split into two non-empty strings such that each string is a palindrome. For example, the string “malamini” can be split into “malam” and “ini” while both of them are palindrome. Another example is “ababab”. It can be split into “aba” and “bab”, and both of them are palindrome. Note that “ababab” can also be split into…Explain with an example the situation where using read() is appropriate andalso an example where readlines() is appropriate.
- Write a function that counts how many concentric layers a rug has. Examples countLayers([ "AAAA", "ABBA", "AAAA" ]) → 2 countLayers([ "AAAAAAAAA", "ABBBBBBBA", "ABBAAABBA", "ABBBBBBBA", "AAAAAAAAA" ]) →3 (Ctrl)The string of terminals generated by CFG: S --> as | bS | bA; A --> bB; B --> aB | bB | λ O A. has at least one b O B. contain substring bb O C. has at least two b's O D. should end with b: The set of all strings from b(b+c)* are * {cb,bbc,bcc,} O {b,bb,bc,bbb,bcc,..} O {b,ab,bc,..} O None of the above O