Given the laboratory results of the Atterberg Limits Test in the figure, plot the water content versus the number of blows.A. Liquid LimitTest Number123Number of blows35282015Weight of Wet Soil + Container, gWeight of Dry Soil + Container, gWeight of Container, gWeight of Water, 8Weight of Dry Soil, gWater Content, %A. Plastic Limit and Natural Water Content91.57108.16119.14114.9473.7885.0489.5684.1021.4522.5620.7819.86Plastic LimitNatural Water ContentTest NumberWeight of Wet Soil + Container, gWeight of Dry Soil + Container, gWeight of Container, gWeight of Water, gWeight of Dry Soil, gWater Content, %Average, %11224.4626.7330.528.1121.7923.4424.6423.6912.4513.2112.3213.24Determine the nearest value to the Liquidity Index of the soil.

The liquidity index is helpful for measuring the natural water content present in the soil Liquidity…

Given the laboratory results of the Atterberg Limits Test in the figure, plot the water content versus the number of blows. A. Liquid Limit Test Number Number of blows Weight of Wet Soil + Container, g Weight of Dry Soil + Container, g Weight of Container, g Weight of Water, g Weight of Dry Soil, g Water Content, % A. Plastic Limit and Natural Water Content 2 3 4 35 28 20 15 91.57 108.16 119.14 114.94 73.78 85.04 89.56 84.10 21.45 22.56 20.78 19.86 Plastic Limit Natural Water Content Test Number Weight of Wet Soil + Container, g Weight of Dry Soil + Container, g Weight of Container, g Weight of Water, g Weight of Dry Soil, g Water Content, % Average, % 2 1 24.46 26.73 30.5 28.11 21.79 23.44 24.64 23.69 12.45 13.21 12.32 13.24 Determine the nearest value to the Liquidity Index of the soil.

Given the laboratory results of the Atterberg Limits Test in the figure, plot the water content versus the number of blows. A. Liquid Limit Test Number Number of blows Weight of Wet Soil + Container, g Weight of Dry Soil + Container, g Weight of Container, g Weight of Water, g Weight of Dry Soil, g Water Content, % A. Plastic Limit and Natural Water Content 2 3 4 35 28 20 15 91.57 108.16 119.14 114.94 73.78 85.04 89.56 84.10 21.45 22.56 20.78 19.86 Plastic Limit Natural Water Content Test Number Weight of Wet Soil + Container, g Weight of Dry Soil + Container, g Weight of Container, g Weight of Water, g Weight of Dry Soil, g Water Content, % Average, % 2 1 24.46 26.73 30.5 28.11 21.79 23.44 24.64 23.69 12.45 13.21 12.32 13.24 Determine the nearest value to the Liquidity Index of the soil.

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter7: Permeability

Section: Chapter Questions

Problem 7.23P

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Given the tabulated data for an Atterberg Limit Test. A. LIQUID LIMIT Test Number No. of blows Weight of Wet soil + container 22.24g 21.19g Weight of Dry soil + container 20.10g| 19.28g Weight of Container 1. 2 39 30 12.74g 13.24g . Test Number No, of blows Weight of Wet soil + container 21.27g 26.12g Weight of Dry soil + container 19.25g 22.60g Weight of Container 3 4 23 12 2/2 13.06g 13.27g B. PLASTIC LIMIT Test Number 2 Weight of Wet soil + container 22.12g 21.84g1 Weight of Dry soil + container 20.42g 20.19g Weight of Container 13.07g 13.18g C. NATURAL WATER CONTENT Test Number 1 2 Weight of Wet soil + container 17.53g 16.97g Weight of Dry soil + container 14.84g| 14.36g Weight of container 7.84g 7.50g a. Compute the liquid limit. b. Compute the plastic limit. c. Compute the natural water content. d. Compute the plasticity index. e. Compute the liquidity index
5. A permeameter of 8 cm diameter contains a sample of length 35 cm. Attachments are made it to enable conducting either constant head test or falling head test. The stand pipe used for conducting falling head test has a diameter of 2.5 cm. When constant head test was conducted the loss of head was 100 cm measured on a length of 25 cm. If the rate of flow was 2.7 cc/sec, calculate the coefficient of permeability of soil. If a falling head test is conducted on the same sample in the permeameter find the time taken for head to fall from 150 cm to 100 cm.
Plastic Limit Test: Weight of wet soil + container = 22.12 g Weight of dry soil + container = 21.42 g Weight of container = 13.07 g Natural Water Content Test: Weight of wet soil + container = 17.53 g Weight of dry soil + container = 14.84 g Weight of container = 7.84 g a.) Compute the liquid limit. (Tip: Use normal scale) b.) Compute the plastic limit. c.) Compute the natural water content. d.) Compute the plasticity index. e.) Compute the liquidity index. d.) Compute the consistency index.
III. Using Atterberg's Plasticity Determination Method Determinethe following; a) Plot the Flow Curve and b) Determine the Flow Index c) Computethe Liquid Limit d) and if the Plastic Limit wa. uetermined as PL = 17.545 % what is the Plasticity Index ? Number of Blows Moisture Content,% 15 38.589 20 35.712 29 28.556 32 24.670
Problem C: For Questions 12 to 15. Following are the results from the liquid and plasticlimit tests for a soil. Liquid Limit Test Number of Moisture Blows,N Content (%) 16 42.150 20 40.775 28 39.115 12) From the flow curve what is the liquid Limit ? a) 39.683% b) 40.555 % c) 38.992 % d) 39.875 % 13) If the Plasticlimit is 18.750 % what is its plasticity index? a) 22.431 % c) 21.344 % b) 20.918 % 14) If in-situ moisture content is 31% determine its liquidity index ? c) 0.585 d) 20.819 % a) 0.665 b) 1.59 15) If the percentage of clay-size fraction is 4.831. Based on its Activity,this mineral is more likely to be a) Illites b) kaolinite d) 20.588 c) Attapulgite d) Smectites
SHOW COMPLTE SOLUTION AND THE ANSWERS SHOULD BE IN 4 DECIMAL PLACES.I'LL RATE, TY Given the laboratory results of the Atterberg Limits Test in the following figure, plot the water content versus the number of blows. Determine the ff. ( PLS SHOW COMPLETE SOLUTION AND GRAPH ) A. Determine the nearest value to the Liquid Limit of soil.B. Determine the nearest value to the Plastic Limit of soil.C. Determine the nearest value to the Liquidity Index of soil.
3. A soil sample was taken with a cylindrical metal core having a volume of 300cm³. The soil was saturated with water and then drainage water was allowed to drip. Meanwhile, evaporation of water from the soil was prevented. The drained soil sample weighed 500 g before oven drying and 350 g after oven drying. Calculate the following: a. bulk density (p6) b. moisture content by mass(%0m) and by volume (%0v) c. porosity (assume ps = 2.65 g/cm³) d. cm of water per 100 cm depth of soil %3D
PLS SHOW YOUR COMPLETE SOLUTIONGiven the laboratory results of the Atterberg Limits Test in the following figure, plot the water content versus the number of blows. a. Determine the nearest value to the Liquid Limit of soil. Answer: 47.1%b. Determine the nearest value to the Plastic Limit of soil. Answer: 38.34%c. Determine the nearest value to the Liquidity Index of soil. Answer: 1.55
Required Coefficient of permeability Falling head permeability test is carried out on a soil specimen having cross-sectional area of 60 sq.cm and height of 15 cm. The water level in the stand pipe of diameter of 0.7 cm drops from 90cm to 30 cm in half an hour. What is the coefficient of permeability (cm/s)?
A sample in a variable head permeameter is 8cm in diameter and 10 cm high. The permeability of the sample is estimated to be 10x 10^-4 cm/sec. If it is desired that the head in the stand pipe should fall from 24 cm to 12 cm in 3 min. Determine the size of standpipe which should be used.
A Standard Proctor test has yielded the values shown below. Determine the maximum dry unit weight and its OMC; remember V = 1/30 ft3. No Weight of wet soil (lb) Moisture % 1 3.26 8.24 4.15 10.20 4.67 12.30 4 4.02 14.60 3.36 16.80 2.
For a given soil, the following are given Gs 2.64, moist unit weight = 17 4 kN/m3, and moisture content = 11.51% Determine the weight of water, in kN, to be added per cubic meter of soil to reach 82% degree of saturation. Round off to three decimal places. h> A Moving to another question will save this response. Activte Ruestion 2 of 20 Go to Settings to activate Windows ASUS W R- T Y] G H. V.